What is the standard form of g(x) = (-x-4)(x-3)

Mathematics

1 answer:

Anni [7]3 years ago

8 0

Answer:

g(x) = - x² - x + 12

Step-by-step explanation:

Given

g(x) = (- x - 4)(x - 3)

Each term in the second factor is multiplied by each term in the first factor, that is

- x(x - 3) - 4(x - 3) ← distribute both parenthesis

= - x² + 3x - 4x + 12 ← collect like terms

= - x² - x + 12 ← in standard form

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2 years ago

three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are

goldenfox [79]

We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
the coordinates of point (x,y) on the terminal ray of angle theta are
x=-5
y=12

the answer is
point (-5,12)

see the attached figure