D=dog's weight
c=cat's weight
d=7c
d+c=72
sub 7c for d
7c+c=72
8c=72
divide both sides by 8
c=9
d=7c
d=7(9)
d=63
dog=63lb
If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.
the sqrt525^7 = 3359983566.19
So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.
(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)
Answer would be 140 why does my answer need to be 20 words long ugh
Answer: She has 1 5/6 exercises for homework.
Step-by-step explanation:
1/2 + 2/3 = 1 1/6
2 * 3 = 6 3 * 2 = 6
1 * 3 = 3 2 * 2 = 4
4 + 3/ 3 + 3
7/6 = 1 1/6
So, she finished 1 1/6 of her problems.
3 - 1 1/6 = 1 5/6
3 - 1 = 2
2 - 1/6 = 1 5/6
M = 1.5 = 3/2
y = mx + b
b = y - mx = 4 - (3/2)6 = 4 - 9 = -5
So equation of the line is:
y = 3x/2 - 5
