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Maksim231197 [3]
2 years ago
13

Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of one-half ?

Mathematics
2 answers:
cricket20 [7]2 years ago
6 0
It would be 3 inches by four inches. answer is 1. 3 in by 4 in. 
Alexeev081 [22]2 years ago
3 0
Hey there! :)

one-half = divide by 2

All you have to do is divide the dimensions by 2

6 ÷ 2 = 3
8 ÷ 2 = 4

The dimensions are 3 in by 4 in ⇒ 1

Hope this helps :)
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Compete the square to determine minum or maxuim value of function define by -x2+10x+5
HACTEHA [7]

Answer:

maximum value y = 30

Step-by-step explanation:

Given

- x² + 10x + 5

To complete the square the coefficient of the x² term must be 1

factor out - 1

= - (x² - 10x) + 5

To complete the square

add/subtract ( half the coefficient of the x- term )² to x² - 10x

= - (x² + 2(- 5)x + 25 - 25) + 5

= - (x - 5)² + 25 + 5

= - (x - 5)² + 30 ← in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Hence vertex = (5, 30)

The max/ min occurs at the vertex

Since a < 0 then vertex is a maximum

Hence maximum value is y = 30

3 0
3 years ago
For the following right triangle, find the side length x. Round your answer to the nearest hundredth
MArishka [77]
The answer is 14.97
8 0
3 years ago
What is the quotient of -27.37% ÷ 7.5
PolarNik [594]

Answer:

-3.649% or -0.0365

Step-by-step explanation:

A percentage can be converted to a decimal by moving the decimal point 2 places to the left.

-27.37% = -0.2737

Divide

-0.2737 / 7.5 = Answer

6 0
3 years ago
Write the following equations in slope intercept form
Rus_ich [418]

Answer:

problem 1 2x+5y= 0

×=-1/2-5/2y

problem 2 y=1 3/7y y=-1.428571

7y=-10

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problem 4 x-y=20

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7 0
3 years ago
Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w
aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0
3 years ago
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