2008 payan walang yan ha kaya mo yan
Answer:2.0736
Step-by-step explanation:
Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).
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Answer:
around 4.1
Step-by-step explanation:
Using Pythaogrean theorem we get <em>sqrt 32</em> or <em>4sqrt2 </em>for the diagonal of the square.
To get x we can use Pythagorean theorem again to set up an equation,
32 + x^2 = 49
This gives us x = <em>sqrt17,</em> which is approximately 4.1231 or around 4.1