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Mariana [72]
2 years ago
12

1. A zoo has 340 animals and then increases the number of animals by 5%. How many animals are at the zoo now?

Mathematics
2 answers:
ss7ja [257]2 years ago
8 0

Answer:

357

Step-by-step explanation:

Multiply: 340*1.05=357

Elodia [21]2 years ago
3 0
367.5
340 + 5% = 367.5
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Is the difference of two rational numbers always rational? Explain
Dominik [7]
The product of two integers is an integer; the difference of two integers is an integer; a rational is defined as one integer divided by another non-zero integer.<span> 

the diference of two numbers is always rational</span>
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=15j%2B5j%2B2jx%5E%7B2%7D" id="TexFormula1" title="15j+5j+2jx^{2}" alt="15j+5j+2jx^{2}" align="
denis23 [38]
Add 15j and 5j it gets u 20j + 2jz^2
3 0
2 years ago
Consider the region, R, bounded above by f(x)=x2−6x+9 and g(x)=−3x+27 and bounded below by the x-axis over the interval [3,9]. F
Salsk061 [2.6K]

Answer:

22.5

Step-by-step explanation:

The region R contains every point of the plane with coordinate x between 3 and 9, and with coordinate y positive such that y < f(x) and y < g(x).

We can note that both f and g are positive on [3,9] because g is a decreasing linear function and g(9) = 0, thus g is positive in every other point of the interval, and f(x) = (x-3)^2 is always positive excpept when x = 3, where it reaches the value 0.

The interception of the graphs takes place for a value x such that f(x) = g(x).

We compute x^2-6x+9 = -3x + 27, thus x^2-6x+9-(-3x + 27) = x^2-3x -18 = 0.

The roots of that quadratic function are

r_1, r_2 = \frac{3 ^+_- \sqrt { 9 +72}}{2} = \frac{3^+_-9}{2} , thus r1 = 6, r2 = -3. We dont care about -3 because it is outside the interval, but we know that f and g graphs intersects on x = 6. Thus, we obtain, due to Bolzano Theorem:

  • On the interval [3,6), the function f in smaller because it takes the value 0 on x=3, while g is always positive.
  • On the interval (6,9]. the function g is smaller because it takes the value 0 on x=9, while f is always positive

Hence, the upper bound is f on the interval [3,6) and g on the interval (6,9]. While the lower bound is the 0 function.

We need to calculate the following integral, using Barrow's rule

\int\limits^6_3 {x^2-6x+9} \, dx + \int\limits^9_6 {-3x+27} \, dx = (\frac{x^3}{3} - 3x^2 + 9x) |^6_3 + (\frac{-3x^2}{2} + 27x)|^9_6 = \\  (18 - 9) + (121.5-108) = 22.5

As a result, the area of the region R is 22.5

6 0
3 years ago
How do you solve this equation: 1988 = 28(p + 15)
WINSTONCH [101]

Answer:

see Below

Step-by-step explanation:

Let's solve your equation step-by-step.

1988=28(p+15)

Step 1: Simplify both sides of the equation.

1988=28(p+15)

1988=(28)(p)+(28)(15)(Distribute)

1988=28p+420

Step 2: Flip the equation.

28p+420=1988

Step 3: Subtract 420 from both sides.

28p+420−420=1988−420

28p=1568

Step 4: Divide both sides by 28.

28p

28

=

1568

28

p=56

Answer:

p=56

4 0
3 years ago
Find the greatest common factor (3x^4y^2+12x^2y^3+6x^3y4)
aleksley [76]

Answer:

3x^2y^2

Step-by-step explanation:

the gcf is 3x^2y^2 since it is the common factor in all of the terms

6 0
3 years ago
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