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3 years ago

7.4 Centimeters to kilometers

Mathematics

1 answer:

Ket [755]3 years ago

7 0

Answer:

.00074 km

Step-by-step explanation:

7.4 cm * 1 m * 1km =7.4/100/100=.00074

100 cm 100m

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(trigonometry) write the tangent ratios for angle P and angle Q. if needed reduce fractions

nevsk [136]

Answer:

Step-by-step explanation:

tan P = $\frac{16}{12}$ = $\frac{4}{3}$

tan Q = $\frac{3}{4}$

7 0

3 years ago

A sphere has a radius of 6 inches. What is the volume of the sphere in terms of π? V = π in.3

Harrizon [31]

Answer: 288pi in3

Step-by-step explanation:

Volume of a sphere= 4/3pir^3

R=6inches

V=4/3pir^3

V=4/3pi(6^3)

V=4/3pi(216)

V=864pi/3

V=288pi in^3

5 0

3 years ago

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A basketball court has a rectangular shape with a length of 94 feet and a width of 50 feet. Janet made two scale models if the r

Irina-Kira [14]

Answer:

Step-by-step explanation:

Note that there are two scale models with each of ratio of 1/2 and 1/16 respectively.

For the first model, the dimension will be as follows:

Length/2 by width/2

94/2 by 50/2 = 47 feet by 25 feet.

For the second model, the dimension will be as follows:

Length/16 by width/16

The dimensions of the second model is 94/16 by 50/16 = 5.875 feet by 3.125 feet.

Since we are to solve for the area of the smallest scale model which is

5.875 feet by 3.125 feet.

Hence, area (A) = L× W

=5.875 × 3.125 feet.

= 18.359ft^2

4 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago

PLEASE HELP!!!

Svetradugi [14.3K]

B or c for the equation because it is 1-n

8 0

3 years ago

Read 2 more answers