Question

The tile along the edge of a triangular community pool needs to be replaced.

Answer 1

Answer:

Third option: 12x^2+8x+25

Step-by-step explanation:

s1=8x^2

s2=4x^2+15

s3=8x+10

Total perimeter of the pool edge: P

P=s1+s2+s3

Replacing s1, s2 and s3 in the formula above:

P=(8x^2)+(4x^2+15)+(8x+10)

P=8x^2+4x^2+15+8x+10

Adding like terms:

P=12x^2+8x+25

Answer 2

Answer:

$12x^2+8x+25$

Step-by-step explanation:

We are given that

Perpendicular length side of triangle  =$4x^2+15$

Base of triangle=$8x+10$

Hypotenuse of right triangle =$8x^2$

We have to find the expression which represents the total perimeter of the pool edge.

We know that

Perimeter of triangle=Sum of three sides of triangle

Substitute the values then we get

Perimeter of right triangular pool edge=$4x^2+15+8x+10+8x^2$

Combine like terms

Perimeter of right triangular pool edge=$12x^2+8x+25$

Hence, the perimeter of the pool edge is given by

$12x^2+8x+25$