20% x 50 =(20 / 100) x 50 = (20 x 50) / 100 = 1000 / 100 = 10
answer is 10
Answer:
- 508
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 28 and d = - 34 - (- 28) = - 34 + 28 = - 6, thus
= - 28 + (- 6 × 80) = - 28 - 480 = - 508
V + 6 < 7
subtract 6 from both sides:-
V < 7 - 6
V < 1
Yes
The rule to check if a triplet of numbers can represent the sides of a triangle is the following: the sum of the length of two sides must exceed the third one.
This happens for all possible couples in your case:



1) R
2) A
5) I
7) Q
8) N
9) L
10) H
11) U
12) E
13) Y
Sorry I could on see these ones. The fractions were a bit hard to see but I hope this helped a bit.