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3 years ago

Triangle ABC was dilated using the rule Dy, 5/4

Mathematics

2 answers:

Phantasy [73]3 years ago

4 0

A) 10. You divide 5/4 to get 1.25 and multiply that by 8 to get 10.

Furkat [3]3 years ago

4 0

Answer:

Step-by-step explanation:

I just passed the test :)

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solniwko [45]

The answer will be option 2. 10^4.

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2 years ago

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Please answer this correctly

Keith_Richards [23]

Answer:

10 units

Step-by-step explanation:

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3 years ago

Simplify: 4 x 32 - 3+5x2 = A. 33 B. 43 C. 36 D. 58 E. 34

NeX [460]

I got 155‍♀️ I don’t know cause I did PEMDAS and got 155

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3 years ago

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Find the flux of F=(x^5+y^5+z^5-2x-3y-4z)i+sin(2y)j+4zsin^2(y)k across the surface of the tetrahedron bounded by the coordinate

Tju [1.3M]

Use the divergence theorem.

$\mathbf F(x,y,z)=(x^5+y^5+z^5-2x-3y-4z)\,\mathbf i+\sin2y\,\mathbf j+4z\sin^2y\,\mathbf k$
$\implies(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial(x^5+y^5+z^5-2x-3y-4z)}{\partial x}+\dfrac{\partial(\sin2y)}{\partial y}+\dfrac{\partial(4z\sin^2y)}{\partial z}=5x^4-2+2\cos2y+4\sin^2y$

The flux of $\mathbf F$ across the tetrahedron's surface $S$ is then given by the integral of $\nabla\cdot\mathbf F$ over the interior of the tetrahedron $\mathbf R$ .

$\displaystyle\iint_S\mathbf F\cdot\mathrm dS=\iiint_T\nabla\cdot\mathbf F\,\mathrm dV$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=1-x}\int_{z=0}^{z=1-x-y}(5x^4-2+2\cos2y+4\sin^2y)\,\mathrm dz\,\mathrm dy\,\mathrm dx$
$=\dfrac1{42}$

4 0

3 years ago

Find the measure of angle AOB

klasskru [66]

Answer:

101°

Step-by-step explanation:

20 + 25 = 45

3+2 = 5

5x + 45 = 180

Subtract 45 from 45 and 180 (both sides)

5x = 135

Divide 5x and 135 (both sides) by 5, to finally get..

x=27

3 x 27 + 20 = 101

2 x 27 + 25 = 79

Angle B.O.C = 79

Angle A.O.B = 101

See the diagram attachment I made down below.

Note:

See the diagram attachment down below. Pls, notify me if my answer is correct, hope this helps, and have a wonderful rest of your day.

- kiniwih426

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3 years ago

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