5.88 / 3 = 1.96 per pound
original price - 1.21 per pound
4 sqrt (32) + 6 sqrt (50)
4 sqrt (16*2) + 6 sqrt (2*25)
4 sqrt (16)*sqrt(2) + 6 sqrt (2)*sqrt(25)
4 *4*sqrt(2)+6sqrt(2)*5
16sqrt(2)+30sqrt(2)
46sqrt(2)
Answer:
x=125
Step-by-step explanation:
∠PAT=180° - ∠ATP - ∠APT
∠PAT=180 - 3x - 3 -4x -4= (173 - 7x)°
3x + 3 + 4x + 4 + 173-7x = 180
⇔x = 125
I’m having a hard time understanding your question
Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :

t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,

The above is a quadratic equation. It can be solved by the formula as follows :

Here, a = -16, b = 32 and c = 128

Neglecting negative value, the projectile will land after 4 seconds.