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lina2011 [118]
3 years ago
9

What point is the center of dilation

Mathematics
2 answers:
fgiga [73]3 years ago
6 0

Answer:

Point E

Step-by-step explanation:

igor_vitrenko [27]3 years ago
4 0

Answer:

The answer is C/Point E

Step-by-step explanation:

I did the test.

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In winter, the price of apples suddenly went up by 0.75 per pound. Sam bought 3 pounds of apples at the new price for a total of
forsale [732]
5.88 / 3 = 1.96 per pound
original price - 1.21 per pound
5 0
3 years ago
Brainliest,plz help
labwork [276]

4 sqrt (32) + 6 sqrt (50)

4 sqrt (16*2) + 6 sqrt (2*25)

4 sqrt (16)*sqrt(2) + 6 sqrt (2)*sqrt(25)

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16sqrt(2)+30sqrt(2)

46sqrt(2)


4 0
3 years ago
Someone thats good at geometry please help asap!
frosja888 [35]

Answer:

x=125

Step-by-step explanation:

∠PAT=180° - ∠ATP - ∠APT

∠PAT=180 - 3x - 3 -4x -4= (173 - 7x)°

3x + 3 + 4x + 4 + 173-7x = 180  

⇔x = 125

4 0
3 years ago
Determine whether each question is biased. Explain your answer. please help!!
LenKa [72]
I’m having a hard time understanding your question
3 0
3 years ago
A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
4 years ago
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