Describe the end behavior of F(x) = x^2 + 4x +3

Mathematics

1 answer:

lina2011 [118]3 years ago

8 0

Answer:

see the explanation

Step-by-step explanation:

we know that

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph

In this problem

we have

$f)x)=x^2+4x+3$

Is a vertical parabola open upward (the vertex is a minimum)

The degree of the function is even (2) and the leading coefficient is positive.

So,

the end behavior is:

f(x)→+∞, as x→−∞

f(x)→+∞, as x→+∞

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