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natali 33 [55]
3 years ago
10

Describe the end behavior of F(x) = x^2 + 4x +3

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

see the explanation

Step-by-step explanation:

we know that

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph

In this problem

we have

f)x)=x^2+4x+3

Is a vertical parabola open upward (the vertex is a minimum)

The degree of the function is even (2) and the leading coefficient is positive.

So,

the end behavior is:

f(x)→+∞, as x→−∞

f(x)→+∞, as x→+∞

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boyakko [2]

Answer:

y=-2.18,-0.22

Step-by-step explanation:

We have been given the equation

(5y+6)^2=24

Take square root both sides. When ever we take square root, we include plus minus sign

\sqrt{(5y+6)^2}=\pm\sqrt{24}\\\\5y+6=\pm2\sqrt6

Now, subtract 6 to both sides of the equation

5y=-6\pm2\sqrt6

Divide both sides by 5

y=\frac{1}{5}(-6\pm2\sqrt6)

y=\frac{1}{5}(-6+2\sqrt6),y=\frac{1}{5}(-6-2\sqrt6)

In decimal we have

y=-2.18,-0.22



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