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natali 33 [55]
3 years ago
10

Describe the end behavior of F(x) = x^2 + 4x +3

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0

Answer:

see the explanation

Step-by-step explanation:

we know that

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity.

The degree and the leading coefficient of a polynomial function determine the end behavior of the graph

In this problem

we have

f)x)=x^2+4x+3

Is a vertical parabola open upward (the vertex is a minimum)

The degree of the function is even (2) and the leading coefficient is positive.

So,

the end behavior is:

f(x)→+∞, as x→−∞

f(x)→+∞, as x→+∞

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Answer:

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Step-by-step explanation:

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Jenna solved the equation 2x^2 +5x - 42 = 0 . She stated that the solutions to the equation were 7/2 and -6. Do you agree with J
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Answer:

Yes. Her solution is correct.

Step-by-step explanation:

Let's check if Jenna solution is correct:

To solve the equation 2x^2 +5x - 42 = 0, we can use Bhaskara's formula:

D = b^2 - 4ac = 25 + 4*2*42 = 25+336 = 361

sqrt(D) = 19

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Answer:

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Step-by-step explanation:

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Hope it will help :)❤

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