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3 years ago

Dalinda spins a spinner 60 times the table shows her data

Mathematics

1 answer:

valkas [14]3 years ago

5 0

Answer:

huh? where is the table, im sorry cant solve this

Step-by-step explanation:

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Help please really needed

Anarel [89]

Answer:

Either :

1/2 10x+1/2 20y+1/2 10z

5x+10y+5z

Step-by-step explanation:

You're just multiplying everything by 1/2

7 0

2 years ago

The measures of the angles of a triangle are shown in the figure below. Solve for x.

Triss [41]

Answer:

Step-by-step explanation:

I can't see anything attached but I know all angles of a triangle add up to 180 degrees. It probably doesn't help tho.

7 0

3 years ago

Read 2 more answers

The sandwiches at the bakery come in four sizes:

kaheart [24]

13 kids sandwiches X 4 inches = 52 inches
22 small sandwiches X 6 inches = 132 inches
17 medium sandwiches X 8 inches = 136 inches
17 large sandwiches X 12 inches = 204 inches

52+132+136+204= 524 inches = 43.66 feet = 43.7 feet

7 0

3 years ago

A 8-sided number die is rolled exactly once. Which statement is correct?

UkoKoshka [18]

Answer:

what statement if it is statistics it is 1/8 chance to get any number between 1-8

Step-by-step explanation:

3 0

2 years ago

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago