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RideAnS [48]
3 years ago
13

How would you multiply fractions to whole numbers?

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0
A whole number is essentially a fraction that looks like this
 36 =\frac{36}{1}

if you remember anything about multiplying fractions
\frac{a}{b} *\frac{c}{d} = \frac{a*c}{b*d}
soldi70 [24.7K]3 years ago
4 0
1)24 2)21..............
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NEED THIS ANSWER BY THE END OF THE DAY PLEASE HELP !!
Alborosie

Answer:

small number is 14

Larger number is 31

Step-by-step explanation:

Let x = one number

Let y = the second number

x + y = 45

x = y - 17

Put y - 17 into the top equation for x

y - 17 + y = 45

2y - 17 = 45          Add 17 to both sides

2y = 45 + 17

2y = 62                Divide by 2

y = 62/2

y = 31

3 0
3 years ago
Which expression is equivalent to 4 square root<br> Of x^10
Airida [17]

A is the answer to this question

4 0
3 years ago
Find the distance between (2.7,5.1) and (3,4.7)
LUCKY_DIMON [66]

Answer:

Distance = 0.5

Step-by-step explanation:

A(2.7 , 5.1)  B(3 , 4.7)

                    D = √((4.7 - 5.1)² + (3  - 2.7)²)

                     D = √(12² + 5²)

                     D = 0.5

3 0
3 years ago
F (x)=×^3+x even or or neithet
Lyrx [107]
My answer.. Replace x with -x and compare.
8 0
3 years ago
A bank manager has developed a new system to reduce the time customers spend waiting for teller service during peak hours. The m
solong [7]

Answer:

Both the approach gave the same conclusion:

There is enough evidence to support the claim that the mean waiting time is shorter than six minutes

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 6 minutes

Sample mean, \bar{x} = 5.46 minutes

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 2.475 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 6\text{ minutes}\\H_A: \mu < 6\text{ minutes}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{5.36 - 6}{\frac{2.475}{\sqrt{100}} } = -2.5858

a) Use the critical value approach

Now, t_{critical} \text{ at 0.05 level of significance, 99 degree of freedom } = -1.6603Since, the calculated test statistic is less than the critical value of t, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that new system reduces the time customers spend waiting for teller service during peak hours from the current 9 to 10 minutes to less than 6 minutes.

b) Use the p-value approach

The p-value can be calculated as:

P-value = 0.0055

Since the p-value is less than the significance level, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

Thus, there is enough evidence to support the claim that new system reduces the time customers spend waiting for teller service during peak hours from the current 9 to 10 minutes to less than 6 minutes.

5 0
4 years ago
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