Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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Answer:
C.Infinitely many solutions
I solved by substitution
Infinitely many solutions
Answer:
I think its linear so I dont know 100% but I think it's a sorry if I'm wrong
3b) 4 tickets/$16 = 0.25 tickets/$1
4a & 4b) You didn’t provide a photo of the problems that I need to solve them
4c) ($4/1 ticket) x (1000 tickets) = $4000
Answer:
68/35 hope this helps
Step-by-step explanation: