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Reika [66]
3 years ago
8

Find the equation that has a slope of - 1/8 and passes through the point (0.-4)

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0

Answer:

ez, answer choice number 4

Step-by-step explanation:

y=-1/8x(this is the slope) -4(this is the y intercept

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Point A is located at (-3, -5)
Vikki [24]

Answer:

(-9, -3)

Step-by-step explanation:

x = -3

y = -5

(x – 6, y + 2)

x = -3 - 6 = -9

y = -5 + 2 = -3

(-9, -3)

8 0
4 years ago
Algebra!!!<br> 3 Questions Only take if you know ALL Answers<br> PLZZZ QUICK
vitfil [10]

Answer:

1. -7.5

2. $1

3. 40

Step-by-step explanation:

For number 1, it can be solved by using the PEMDAS method, or see explanation below:

6x - 4x - 36 = 6 - 2x

2x - 36= -2x + 6

4x + 36 = 6

4x = -30

x = -15/2 or -7.5

For number 2, substitute 3 into both equations:

f(x) =1.50(3) + 2.00

and

f(x) = 2.00(3) + 1.50

This would get $6.50 and $7.50, which, if subtracted, gets $1.

For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.

Hope this helps!

7 0
3 years ago
What is the equation that represents the line
KiRa [710]

Answer:

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

Step-by-step explanation:

5 0
3 years ago
The table shows the relationship between the number of songs Alisha has purchased and the cost of her purchase. Find the rate of
Gre4nikov [31]

Answer:

whats the question

Step-by-step explanation:

4 0
3 years ago
Greg is trying to solve a puzzle where he has to figure out two numbers, x and y. Three less than two-third of x is greater than
Fittoniya [83]
Inequation 1: 

\frac{2}{3}x-3 \geq y

to plot the pairs (x, y) for which the inequation holds, draw the line y=\frac{2}{3}x-3

then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.

we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.

inequation 2: 

y+ \frac{2}{3}x\ \textless \ 4

y\ \textless \ - \frac{2}{3} x+ 4&#10;


draw the lines 

i)  y=\frac{2}{3}x-3          use points (0, -3),  (3, -1)

ii)y=- \frac{2}{3} x+ 4       use points ( 0, 4),   (3, 2)


let's use the point P(3, 3) to see what region of the lines need to be coloured:

\frac{2}{3}x-3 \geq y  ; 
\frac{2}{3}(3)-3 \geq 3
2-3 \geq 3, not true so we color the region not containing this point


y+ \frac{2}{3}x\ \textless \ 4
(3)+ \frac{2}{3}(3)\ \textless \ 4
3+ 5\ \textless \ 4 not true, so we color the region not containing the point (3, 3)

The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.



4 0
3 years ago
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