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goldfiish [28.3K]
3 years ago
13

Which conclusion is supported by the data from the multiple-year samples? Check all that apply

Mathematics
2 answers:
dedylja [7]3 years ago
4 0

Answer:

B and C

Step-by-step explanation:

Natasha2012 [34]3 years ago
3 0

Answer:

Hello There!

The correct answers are B: The number of bass decreased over time and C: The number of catfish increased over time.

Step-by-step explanation:

This is simply what the chart shows, as well as I got this correct on Edge :)

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The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot
MaRussiya [10]
I found the corresponding image. Pls. see attachment.

<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>

8 0
3 years ago
If AJKL = AMNP, which statement must be true?
Karo-lina-s [1.5K]
Where are the statements
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3 years ago
Read 2 more answers
5 (3y — 13) = бу – 2<br> PLEAse help <br> Need those 2
____ [38]

Answer:

y = 7

Step-by-step explanation:

5(3y - 13) = 6y - 2

5*3y + 5*-13 = 6y - 2

15y - 65 = 6y - 2

15y - 6y = 65 - 2

9y = 63

y = 63/9

y = 7

Check:

5((3*7)-13) = 6*7 - 2

5(21-13) = 42 - 2

5*8 = 40

6 0
3 years ago
Christine owns 9 hair bands and additional hair bands are 2 for a dollar. How much money does she need to spend on hair bands in
kirill [66]

Answer: $20

Step-by-step explanation:

If she already has 9, and she needs 49, take that extra 9 off 49 and then she needs 40 more and she gets 2 for a dollar, she'll need to spend $20 to get 40 headbands. Can I please get Brainliest?

7 0
3 years ago
What are the zeros in the function
Schach [20]
f(x)=x^3+x^2-6x\\\\text{The zeros:}\\\\f(x)=0\to x^3+x^2-6x=0\\\\x(x^2+x-6)=0\\\\x(x^2+3x-2x-6)=0\\\\x[x(x+3)-2(x+3)]=0\\\\x(x+3)(x-2)=0\iff x=0\ \vee\ x+3=0\ \vee\ x-2=0\\\\x=0\ \vee\ x=-3\ \vee\ x=2

Answer: -3; 0 and 2

6 0
3 years ago
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