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2 years ago

In parallelogram KLMN, NL=15. Identify NP. HELP PLEASE!!

Mathematics

1 answer:

adelina 88 [10]2 years ago

7 0

Answer:

Step-by-step explanation:

Fact: The diagonals of a parallelogram bisect each other. If NL= 15 the NP = 1/2 NL

1/2 NL = 15/2 = 7.5.

NP = 7.5

Answer: NP = 7.5 B

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3 years ago

Line I is parallel to line m. If the measure of <6 is 75, what is the measure of <3

Nady [450]

Answer:

m∠3 = 105°

Step-by-step explanation:

Line 'l' is parallel to line 'm' and a transversal is intersecting these parallel lines at two distinct points.

m∠3 + m∠6 = 180° [Consecutive interior angles]

Since, ∠6 = 75° [Given]

m∠3 + 75° = 180°

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garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

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-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

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Answer:

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