Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
it can not go any more
Step-by-step explanation:
7/45 is the simplified terms
Answer: y = 25x + 50
Explanation: the total cost if the rental is a linear function of the number of days of the rental (x). Each day costs $25, so that is the slope of the line. Since there is also a one-time fee, independent of the number of days, this amount $50 represents a vertical shift of the line on the graph, by 50. y=25x+50 is an algebraic expression of that.
Answer:
give me brainliest now plsssss
Step-by-step explanation:
(8x-22)=5x+29
We move all terms to the left:
(8x-22)-(5x+29)=0
We get rid of parentheses
8x-5x-22-29=0
We add all the numbers together, and all the variables
3x-51=0
We move all terms containing x to the left, all other terms to the right
3x=51
x=51/3
x=17
Answer:
D
Step-by-step explanation:
slope = rise / run
slope = (5 - 3) / (-2 - 2)
slope = 2 / -4
slope = -2 / 4
slope = -1/2