1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodka [1.7K]
4 years ago
15

Solve for u in the proportion. 40/15 = u/6 URGENT

Mathematics
2 answers:
fenix001 [56]4 years ago
6 0

Answer:

16

Step-by-step explanation:

40 \div 15 = x \div 6 \\ 40 \div 5 = x \div 2 \\  \\ 5x = 80 \\ x = 16

sammy [17]4 years ago
4 0

Answer:

16

Step-by-step explanation:

40x 6 =u x 15

240=u x 15

U = 240÷15

U = 16

You might be interested in
31. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
Whitepunk [10]

Answer:

The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

and f(5)=1. linear equation of the line in the form

$$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

This means that the function f(x) satisfies the points (-1,4) and (5,1).

Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

$(y-1)=\frac{-1}{2}(x-5)$

Distribute $\frac{-1}{2}$,

$y-1=\frac{-1}{2} x+\frac{5}{2}$

Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$$

So, this is the required linear equation.

8 0
2 years ago
How long will it take to earn $252 in interest if $1200 is invested at a 7% annual interest rate?
zheka24 [161]
T=i/pr
t=252÷(1,200×0.07)
t=3 years
4 0
3 years ago
Lacey picks blueberries and raspberries from her garden. She has ⅕ as many pounds of blueberries as raspberries. If she picks 1⅘
Mrac [35]

Answer:

  • 2 1/4 pounds of blueberries

Step-by-step explanation:

Blueberries - b, raspberries - x

<u>Equations as per question:</u>

  • b = x * 1/5
  • b + 1 4/5 = x

<u>Eliminate b and solve for x:</u>

  • 1/5x = x - 1 4/5
  • x - 1/5x = 1 4/5
  • 4/5x = 9/5
  • x = 9/5 : 4/5
  • x = 9/5 *5/4
  • x = 9/4
  • x = 2 1/4
5 0
3 years ago
Read 2 more answers
Is △FHK similar to △GHJ? If so, which postulate or theorem proves these two triangles are similar? ​△FHK​ ​ is similar to ​ ​△GH
blagie [28]

Answer:

ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.

Step-by-step explanation:

Picture for the given question is missing; find the picture attached.

If \frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}} and ∠H ≅ ∠H

Then ΔFHK ~ ΔGHJ

\frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}}

\frac{(12+10)}{10}=\frac{(15+18)}{15}

\frac{22}{10}=\frac{33}{15}

\frac{11}{5}=\frac{11}{5}

Since, \frac{\text{FH}}{\text{GH}}=\frac{\text{HK}}{\text{HJ}} and ∠H ≅ ∠H [By reflexive property]

Therefore, ΔFHK and ΔGHJ are the similar triangles by SAS similarity theorem.

Option (3) will be the answer.

4 0
4 years ago
A particle moves on the circle x2 y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=
stiks02 [169]

The movement of the particle on the circle is its displacement.

The value of dy/dt at this time is -9/2.

<h3>What is the differentiation?</h3>

Differentiation is a process, in Maths, where we find the instantaneous rate of change in function based on one of its variables.

A particle moves on the circle x^2 + y^2=25 in the XY-plane for time t≥0. At the time when the particle is at the point (3,4), dxdt=6.

The equation of the circle is given as:

\rm x^2 + y^2=25

Differentiate with respect to time

\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0

Substitute all the values in the equation

\rm 2x \times \dfrac{dx}{dt}+2y \times \dfrac{dy}{dt}=0\\\\2(3) \times 6+2(4)\times \dfrac{dy}{dt}=0\\\\ 6 \times 6+8 \times \dfrac{dy}{dt}=0\\\\  36+8\times \dfrac{dy}{dt}=0\\\\ 8\times \dfrac{dy}{dt}=-36\\\\ \dfrac{dy}{dt}= \dfrac{-36}{8}\\\\ \dfrac{dy}{dt}= \dfrac{-9}{2}

Hence, the value of dy/dt at this time is -9/2.

Learn more about differentiation here;

brainly.com/question/19385433

#SPJ4

6 0
2 years ago
Other questions:
  • the three sides of a triangle are n, 3n+2, and 4n−4. If the perimeter of the triangle is 54cm, what is the length of each side?
    13·2 answers
  • There are 225 students at March middle school. On Friday, 135 students wore spirit shirts. What percent of the students did Not
    8·1 answer
  • If -2x = -14 what is the value of x
    6·2 answers
  • 18 1/2 -2^3•(4 1/3 + 6 4/6)
    11·1 answer
  • Every day, 500 airplanes in San Francisco incur an additional 30 minutes of airport delays when flying into or out of the airpor
    8·2 answers
  • Which of the following is an undefined term? (6 points)
    11·1 answer
  • Find the degree of the polynomial
    6·1 answer
  • Writethecoordinatesoftheverticesafteradilationwithascalefactorof 1 5 ,centeredattheorigin. y x -10 10 -10 10 0 S T U S(5, -10) →
    6·2 answers
  • Does anyone know 8g–4g+10g ??
    15·2 answers
  • Circumference of the circle
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!