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Vinvika [58]
3 years ago
6

9x+3=3x+9Slove for x?

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
Let's review: 
<span><u>Inverse Operations:</u>
</span>Inverse Operations are operations which undo each other!
I'll give the following Inverse Operations in this form.

Operation -> Inverse Operation

Addition -> Subtraction
Subtraction -> Addition

Multiplication -> Division
Division -> Multiplication

That's all of them we'll need to know to solve this problem! 

9x + 3 = 3x + 9

First Step!: Move all of the variables to once side (Numbers with x in them). (Prioritize the lower one so we won't need to work with negative numbers) Subtract 3x on both sides (Subtract, because the number is positive) 

9x - 3x + 3 = 3x - 3x + 9

3x - 3x = 0 

9x - 3x + 3 = 9 

Move the 3 to the right by subtracting it on both sides. 

9x - 3x + 3 - 3 = 9 - 3

3 - 3 = 0 
9 - 3 = 6

9x - 3x = 6 

Subtract like terms. (Just like you would subtract 9 - 3). Note that they are only like terms, because they both have the same variables (x) that are the same power (1).

6x = 6 

Divide 6 on both sides to get your answer.

6x/6 = 6/6 

The 6's cancel out and we are left with 1 on the left AND right, because 6/6 = 1. 

x = 1

Plug x in to check.

9(1) + 3 = 3(1) + 9 

9 + 3 = 9 + 3 

Those are definitely equal!

I hope that helped. If it did then consider giving me the brainliest answer. Thanks.
Alex Ar [27]3 years ago
7 0
9x + 3=3x + 9....so 9x-3x=: 3 = -3x+9 and then you minus 9 from 3 and it equals to -3=-3x and then you divided -3 by -3 equals 
=1 negative divided by a negative "always" a positive. so the answer is  (positive one)
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The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

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When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305

The degrees of freedom for this sample size are:

df=n-1=50-1=49

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.01 \cdot 0.305=0.61

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95

The 95% confidence interval for the mean is (5.73, 6.95).

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