3 years ago

What is the initial value of h(t)= -9.8t2+48t+50?

Mathematics

2 answers:

Luba_88 [7]3 years ago

8 0

48 is the correct answer

garik1379 [7]3 years ago

7 0

Answer:

$h(t) = 9.8 {t}^{2} + 48t + 50 \\ initially : \: t = 0 \\ h(0) = 50$

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