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galben [10]
3 years ago
15

What is the initial value of h(t)= -9.8t2+48t+50?

Mathematics
2 answers:
Luba_88 [7]3 years ago
8 0
48 is the correct answer
garik1379 [7]3 years ago
7 0

Answer:

h(t) = 9.8 {t}^{2}  + 48t + 50 \\ initially :  \: t = 0 \\ h(0) = 50

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What is the area of this figure?
insens350 [35]

Answer:

54 units squared

Step-by-step explanation:

You have to divide the shape into simpler shapes such as rectangles and triangles that you can easily find the area of. Then, add those areas together. I divided it into one rectangle and three triangles.

Rectangle 1: length=7 width=6          6(7)=42

Triangle 1: base=6 height=2          1/2(6)2=6

Triangle 2: base=3 height=2          1/2(3)2=3

Triangle 3: base=6 height=1          1/2(6)1=3

Area= R1+T1+T2+T3= 42+6+3+3= 54 units squared

5 0
3 years ago
Read 2 more answers
Please help extra points cuz ik this will be hard and some time to do
vesna_86 [32]

Answer

Part A

1 - 1

2 - 3

3 - 6

4 - 10

5 - 15

Part B

Now plot these points on the coordinate plane

(1,1) (2,3) (3,6) (4,10) (5,15)

Part C

It is NOT a linear function

4 0
3 years ago
Read 2 more answers
9n+21−3n−24 simplify
Thepotemich [5.8K]
Alright First you combine the like terms. 
9n - 3n = 6n 
21 - 24 = -3 

Rewrite the simplified equation
6n - 3 = 0

Solve for n 
6n = 3 
n = 3/6 
n = 1/2 

Ask if you need more help! :)

6 0
3 years ago
UREGNT -- BRAINLIEST!
Nady [450]

Answer:

12

Step-by-step explanation:

∛1728 = ∛2*2*2*2*2*2*3*3*3*3 = 2*2*3 = 12

3 0
3 years ago
Read 2 more answers
When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for
juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where n= sample size

\hat{p} = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = \hat{p}=\dfrac{106}{258}\approx0.411

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the  99% confidence interval for the true proportion(p) of all college students who own a car will be :0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0
3 years ago
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