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quester [9]
3 years ago
7

Ricardo has two cases of video games with the same number of games in each case he gives four games to his brother Ricardo has 1

0 games left how many video games were in each case
Mathematics
1 answer:
UNO [17]3 years ago
5 0
14 games were in each case
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To find an object’s density (D), first measure its mass (m) and volume (V). Then use the following equation:
Mariana [72]

Answer:

C. 20 cm^3

Step-by-step explanation:

Using the equation D=m/v, you would plug in the given mass (227 g) into m and the given density of lead (11.35 g/cm^3).  Solving for v=m/D, we find the answer to be 20 cm^3.  

Also, you could cancel out all the answers except C because it is the only one in units of volume (1 cm^3 = 1 mL).

7 0
3 years ago
Solve the equation 8x-12=5+15
Anika [276]
8x-12 = 5+15
8x-12 = 20 
     8x = 32      +12 
       x = 4        ÷8

7 0
3 years ago
Read 2 more answers
A total of 366 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t
icang [17]
I will set it up and you finish.

Let a = adult

Let s = students

s = 2a

Here is your system of equations:

a + s = 366
s = 2a

Take it from here.

3 0
3 years ago
What is 60% of 300?
V125BC [204]
Do a proportion
60/100= x/300
60 x 300= 18,000
18,000 divided by 100= 180
Answer is 180

Or you could have done .60 x 300 and got 180.
3 0
3 years ago
Read 2 more answers
A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that t
Korolek [52]

Answer:

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

At the null hypothesis, we test if the proportion is of 75%, that is:

H_0: p = 0.75

At the alternate hypothesis, we test if the proportion is different of 75%, that is:

H_1: p \neq 0.75

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

75% is tested at the null hypothesis:

This means that \mu = 0.75, \sigma = \sqrt{0.75*0.25}

A random sample of 280 found that 70% of the readers owned a particular make of car.

This means that n = 280, X = 0.7

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.7 - 0.75}{\frac{\sqrt{0.75*0.25}}{\sqrt{280}}}

z = -1.93

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion differing from 0.75 by at least |0.7 - 0.75| = 0.05, which is P(|z| > 1.93), which is 2 multiplied by the p-value of z = -1.93.

Looking at the z-table, z = -1.93 has a p-value of 0.0268.

2*0.0268 = 0.0536.

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

5 0
3 years ago
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