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JulsSmile [24]
2 years ago
6

How much is the product of 14 and 16 less than 290

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
4 0

The product of 14 and 16 is 66 less than 290.

<h3>What is the meaning of product ?</h3>

The product is obtained when two numbers are multiplied with each other .

The given data can be used to make an equation

Let the product of 14 and 16  be x less than 290 then

14*16 = 290-x

224 = 290-x

x = 66

Therefore the product is 66 less than 290.

To know more about Product

brainly.com/question/22852400

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Meron ka nang loptap bakit humihingi ka pa nang answer

8 0
3 years ago
Which intervals show f(x) decreasing? Check all that apply.
wolverine [178]

The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

<h3>Which intervals naming the answer choices show the function f(x) decreasing?</h3>

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]

Read more on decreasing intervals;

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4 0
2 years ago
julio says if you subtract 15 from my number and multiply the difference by -7, the result is -42 what is julio number
natali 33 [55]

Answer:

-10

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
On a map, the distance from Akron to Cleveland measures 2 centimeters. What is the actual distance of the scale of the map shows
fredd [130]
60 kilometers because it is 2 cm just multiply by 2
5 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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