Answer:
ayuda wala pa kmi SAP UMAYS
16:29:15 I think that would be it but, I'm really sorry if that's not right
Step-by-step explanation:
your don't see what went wrong ?
Tyrell worked on
16 - 2(4 + 3x)
what do brackets mean ? they mean that this operation has to be done before everything else in the expression.
as this contains a variable, we cannot fully calculate it, true, but we need to keep this in mind and always treat the content of the brackets as one package.
so, whatever I do from the outside with one part of that package, I have to do also with all the other parts of that package.
so, the multiplication with -2 has to happen with both : 4 and 3x. not just with 4.
therefore, the correct simplification looks like
16 - 8 - 6x
8 - 6x or -6x + 8
Amelia multiplied correctly, but then made a mistake summing things up
10x - 3(4x + 1)
10x - 12x - 3
10x - 12x = -2x
I can't mix the pure constant -3 into the factors of x. that would be like the famous mixing of apples and oranges.
so, the result is
-2x - 3
(a) False. The number 7 is NOT an element of set B as 7 is not in the set B (2, 3, 4 and 0 are though)
(b) False. 3 is a member of set A. It is the third element listed in the set. So saying "3 is not a member of set A" is a false claim
(c) True. The value 0 is found in set B. It is the last element listed.
Final Answer: Choice C)
If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
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