Can someone help me with this math equation:f'(x)=-3x^2 +18x-10

Mathematics

1 answer:

12345 [234]3 years ago

5 0

Answer:

the vertex is at (3,17)

it opens downward

the axis of symetry is x=3

Step-by-step explanation:

let me know if you need more info than that.

Hope this helps! :)

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Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

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3 years ago

If f(x-3)=x^2-4x+5, what's f(1-x)

olganol [36]

Answer:

$\large\boxed{f(1-x)=x^2-4x+5}$

Step-by-step explanation:

$f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2$