Answer:
2x^2 + 2y^2 + 2z^2
Step-by-step explanation:
x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
First step is to put all the same ones together
( FYI, xy and yx is the same thing, just like how
2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes
(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +
(z^2 +z^2) + (zx - zx)
2x^2 + 2y^2 + 2z^2
All the others just cancel themselves out, for example, xy-xy
When anything minus themselves it will become 0
Mid point formula =
(x1/2+x2/2, y1/2+y2/2)
x=
x+0 = 8
/2
x+0 = 8 x 2
x = 16
y=
y+(-2) = 1
/2
y-2 =1 x2
y=2+2
y=4
(16,4)
(In this case, the midpoint (x ,y) will be represent as the answer)
