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3 years ago

He will look into the matter.change to passive voice

Mathematics

1 answer:

Veronika [31]3 years ago

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kala used 12.86 gallons of fuel while driving now 1.6 gallons are left how much fuel did kala car have before her trip

Troyanec [42]

Her car had 14.46 gallons of fuel before her trip because 12.86+1.6=14.46

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3 years ago

Which is the equation for the line that has a slope of 12 and passes through the point (3, 20)?

Anna007 [38]

Answer:

the first one

Step-by-step explanation:

y-y1=m(x-x1)

y-20=12(x-3)

$y-20+20=12\left(x-3\right)+20$

simplify:

$y=12x-16$

4 0

3 years ago

Quadrilateral ABCD is similar to Quadrilateral EFGH. Diagonal AC has length 7 and diagonal EG has length 13. What is the scale f

olasank [31]

Answer:

$\large \boxed{\text{A. }\dfrac{13}{7}\text{; B. }\dfrac{17}{14} \text{; C. 507 in}^{2}}$

Step-by-step explanation:

A. Scale factor

When you dilate an object by a scale factor, you multiply its line lengths by the same number.

If EF/AB = 13/7, the scale factor is 13/7.

B. Length of EF

$\begin{array}{rcl}\dfrac{EF}{AB} & = & \dfrac{13}{7}\\\\\dfrac{EF}{\frac{17}{26}} & = & \dfrac{13}{7}\\\\EF & = & \dfrac{13}{7}\times\dfrac{17}{26}\\\\ & = &\dfrac{1}{7}\times\dfrac{17}{2}\\\\ & = & \mathbf{\dfrac{17}{14}}\\\end{array}\\\text{The length of EF is $\large \boxed{\mathbf{ \dfrac{17}{14}}}$}$

C. Area of EFGH

If the lengths in a shape are all multiplied by a scale factor, then the areas will be multiplied by the scale factor squared.

ABCD is dilated by a scale factor of 13/7, so its area is dilated by a scale factor of

$\left(\dfrac{13}{7} \right)^{2} = \dfrac{169}{49}$

The area of its dilated image EFGH is

$\text{Area of EFGH} = \text{147 in}^{2} \times \dfrac{\text{169}}{\text{49}} = 3 \times 169\text{ in}^{2} = 507 \text{ in}^{2}\\\\\text{The area of EFGH is $\large \boxed{\textbf{507 in}^{\mathbf{2}}}$}$

8 0

3 years ago

A circle has An area of 36 pi square inches which best represents the circumference of the circle.

kkurt [141]

Answer: 12πins.

Step-by-step explanation:

Since the area if a circle = πr²

From the question

Area of the circle = 36πins²

To find the circumference of the circle, we need to find the common radius of the circle and this could be achieved from the area of the circle given above.

πr² = 36π, solving this gives. Divide through by π

r² = 36

r = +/-√36

= +/-6

Now to find the circumference of the circle, we substitute for r in the formula below.

Circumstances = 2πr

= 2 ×π × 6

= 12πins.

4 0

3 years ago

What is the solution of the equation? w - 2 = -3

Viktor [21]

I think the answer would be c

6 0

3 years ago

He will look into the matter.change to passive voice​

He will look into the matter.change to passive voice