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topjm [15]
3 years ago
7

The graph of f(x) = xx is reflected across the x-axis and then across the y-axis to create the graph of function g(x).

Mathematics
2 answers:
Lelechka [254]3 years ago
5 0
The answer is C hope that helped
V125BC [204]3 years ago
3 0

Now let's examine the statements:

A)The functions have the same range:FALSE the range changed from y ≥ 0 to y ≤ 0

B)The functions have the same domains. FALSE the doman changed from x ≥ 0 to x ≤ 0

C)The only value that is in the domains of both functions is 0. TRUE: the intersection of x ≥ 0 with x ≤ 0 is 0.

D)There are no values that are in the ranges of both functions. FALSE: 0 is in the ranges of both functions.

E)The domain of g(x) is all values greater than or equal to 0. FALSE: it was proved that the domain of g(x) is all values less than or equal to 0.

F)The range of g(x) is all values less than or equal to 0. TRUE: it was proved above.

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muminat

Answer:

144

Step-by-step explanation:

If you multiply 4 by 12, then add 100, you get 144 which is the area.

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The cost of a jacket was originally 40$ It was on sale for 20% how much did they save
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Answer:

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Step-by-step explanation:

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How do i find the volume of these similar solids? round to the nearest tenth HELP
FromTheMoon [43]

Answer:

The volume of the larger solid is 592.6\ mm^3

Step-by-step explanation:

<u><em>The question is</em></u>

If these solids are similar, find the volume of the larger solid

step 1      

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

z=\frac{x}{y}

we have

x=4\ mm\\y=3\ mm

substitute

z=\frac{4}{3} ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

z^3=\frac{x}{y}

we have

z=\frac{4}{3}

y=250\ mm^3

substitute the values

(\frac{4}{3})^3=\frac{x}{250}

solve for x

(\frac{64}{27})=\frac{x}{250}

x=250(\frac{64}{27})

x=592.6\ mm^3

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2 pages

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