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3 years ago

The length of the side of the cube is 5x units, what is the volume of the cube?

Mathematics

1 answer:

kykrilka [37]3 years ago

3 0

Answer:

The side length of the cube is 5 cm. Then the volume is simply 5\times 5\times5 = 125

LxWxH

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Vectors and scalars (are/arenot) the same

dangina [55]

There not the same
vectors have magnitude and direction scalars on the other hand only have magnitude

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3 years ago

Read 2 more answers

Please answer question now

IceJOKER [234]

The answer is 41.7 km^2

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3 years ago

When will the equation p(b)=520(0.88)^b have a value less than 100?

yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × $0.88^{b}$ to have a value less than 100 we can establish inequality as:

p(b) < 100

or, 520 × $0.88^{b}$ < 100

or, $\frac{520}{520}$ × $0.88^{b}$ < $\frac{100}{520}$

or, $0.88^{b}$ < $\frac{1}{5.2}$

or, ㏒ ( $0.88^{b}$ ) < ㏒ ( $\frac{1}{5.2}$ )

or, b× ㏒ 0.88 < ㏒ ( $\frac{1}{5.2}$ )

or, $\frac{log (\frac{1}{5.2}) }{log (0.88)}$ < b

or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0

4 years ago

Lindsey earns 5% commission off all sales in the clothing boutique she works at. If a customer bought $124.50 in merchandise, ho

goldenfox [79]

Answer:

Choice C: 6.23

Step-by-step explanation:

$\frac{5}{100}$ = $\frac{x}{124.50}$ -----> cross multiply

5(124.50) = 100x

622.5 = 100x

$\frac{622.5}{100} = \frac{100x}{100}$

6.225 = x

6.225 rounded to the nearest hundredth is 6.23

She earned 6.23 commission.

4 0

3 years ago

Polygon PQRS, shown in the figure, is dilated by a scale factor of 0.5 with the origin as the center of dilation, resulting in p

nata0808 [166]

Based on the above:

The slope of P'Q' is = -3/2

The length of P'Q' is approximately = $\sqrt[3]{13}$

<h3>What is the polygon about?</h3>

The slope of P'Q'

= -6/4 = -3/2

The length of P'Q' =

P'Q' = $\sqrt{6^2 + 4^2}$

= $\sqrt{52}$

= $\sqrt[2]{13}$

Therefore;

P'Q' = $\frac{3}{2}$

P'Q' = $\frac{3}{2}$ x $\sqrt[2]{13}$

= $\sqrt[3]{13}$

Learn more about polygon from

brainly.com/question/1592456

#SPJ1

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2 years ago