Answer:$54000
Step-by-step explanation:
8%of50000=4000
4000+50000=54000
Answer:
he multiplied by 0.8 not .08
Step-by-step explanation:
when doing 8% you go back 2 places so 0.08
34×0.08= 2.72
34+2.72= 36.72
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Just took the test and got the the correct answer *\(♡°▽°♡)/*
Look at the image down below!!
D' = (-2, 0) = 2*(-1, 0) = 2*D
The scale factor is 2.
