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Novosadov [1.4K]
4 years ago
12

What is the value of n ??????????

Mathematics
1 answer:
lyudmila [28]4 years ago
4 0

Answer:

it's b 59° because it's at the side

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The bakery sells 8 doughnuts for every 3 bagels sold. If the bakery sells 9 bagels in a day, how many doughnuts are sold?
Lunna [17]

Answer:

24. here is the explanation

if 8 donuts are sold for each 3 bagels sold and the bakery sold 9 in a day. 3x3x3 = 9. and if 8 are for every 3... just multiply 8 x 3 is 24.

Step-by-step explanation:

3 0
4 years ago
Use the disk method or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs
JulsSmile [24]

Answer:

1) V = 12 π  ㏑ 3

2) \mathbf{V = \dfrac{328 \pi}{9}}

Step-by-step explanation:

Given that:

the graphs of the equations about each given line is:

y = \dfrac{6}{x^2}, y =0 , x=1 , x=3

Using Shell method to determine the required volume,

where;

shell radius = x;   &

height of the shell = \dfrac{6}{x^2}

∴

Volume V = \int ^b_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = \int ^3_{x-1} \ 2 \pi ( x) ( \dfrac{6}{x^2}) \ dx

V = 12 \pi \int ^3_{x-1} \dfrac{1}{x} \ dx

V = 12 \pi ( In \ x ) ^3_{x-1}

V = 12 π ( ㏑ 3 - ㏑ 1)

V = 12 π ( ㏑ 3 - 0)

V = 12 π  ㏑ 3

2) Find the line y=6

Using the disk method here;

where,

Inner radius r(x) = 6 - \dfrac{6}{x^2}

outer radius R(x) = 6

Thus, the volume of the solid is as follows:

V = \int ^3_{x-1} \begin {bmatrix}  \pi (6)^2 - \pi ( 6 - \dfrac{6}{x^2})^2  \end {bmatrix} \ dx

V  =  \pi (6)^2 \int ^3_{x-1} \begin {bmatrix}  1 - \pi ( 1 - \dfrac{1}{x^2})^2  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  1 -  ( 1 + \dfrac{1}{x^4}- \dfrac{2}{x^2})  \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  - \dfrac{1}{x^4}+ \dfrac{2}{x^2} \end {bmatrix} \ dx

V  =  36 \pi \int ^3_{x-1} \begin {bmatrix}  {-x^{-4}}+ 2x^{-2} \end {bmatrix} \ dx

Recall that:

\int x^n dx = \dfrac{x^n +1}{n+1}

Then:

V = 36 \pi ( -\dfrac{x^{-3}}{-3}+ \dfrac{2x^{-1}}{-1})^3_{x-1}

V = 36 \pi ( \dfrac{1}{3x^3}- \dfrac{2}{x})^3_{x-1}

V = 36 \pi \begin {bmatrix} ( \dfrac{1}{3(3)^3}- \dfrac{2}{3}) - ( \dfrac{1}{3(1)^3}- \dfrac{2}{1})    \end {bmatrix}

V = 36 \pi (\dfrac{82}{81})

\mathbf{V = \dfrac{328 \pi}{9}}

The graph of equation for 1 and 2 is also attached in the file below.

5 0
4 years ago
Mr. Barrett bought a new battery for his car. The battery cost $72. Since batteries are a taxable item, he had to pay a sales ta
My name is Ann [436]

Answer:

$77 and 40¢

Step-by-step explanation:

7.5 percent of $72 is $5.4 so you would add $5.4 to $72 which makes $77.40.

5 0
3 years ago
If the P-value is 0.02, then means that the confidence interval is 2% 98% indeterminable. 95%
hoa [83]

Answer: 98%

Step-by-step explanation:

In statistics , the P-value gives the significance level of the population parameter in the population.

The significance level is denoted by \alpha.

Level of confidence is given by :-

1-\alpha.

Given : The P-value is 0.02, then the significance level is \alpha=0.02 which can be written as 2%.

Then, the  confidence interval : 1-0.02=0.98. i.e. 98%

6 0
3 years ago
What is the solution set to the inequality
creativ13 [48]

(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant  \frac{3}{4}  \\ x  \geqslant  \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant  \frac{3}{4}  \\x \leqslant  \frac{1}{2}  \end{cases} \\ \Leftrightarrow x \geqslant  \frac{3}{4} \: \vee \: x \leqslant  \frac{1}{2}  \\ \Rightarrow The\: third\: option

5 0
3 years ago
Read 2 more answers
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