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Ainat [17]
3 years ago
11

I NEED HELP NOW!!!!

Mathematics
2 answers:
V125BC [204]3 years ago
4 0

Answer:

89 foreign stamps

123  domestic stamps

Step-by-step explanation:

it's right on ed (:

iris [78.8K]3 years ago
3 0
OKAY listen up
So we have two equations
x - y = 34
x + y =212
Let's take the first equation and put it in terms of x
x-y+y= 34+y
x= 34 + y
Now that we have a value for x, substitute it into the second equation for x and solve for y.
(34+y)+y=212
34+y+y = 212
34+2y= 212
34-34+ 2y=212-34
2y= 178
2y/2=178/2
y= 89
Now that we know the value for y, we can substitute it into the first equation and solve for x.
x-89=34
X-89+89=34+89
X=123
Y= 89
X =123

ANSWER
Domestic Stamps: 123
Foreign Stamps: 89
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Find the component form of the vector that represents the velocity of an airplane at the instant its wheels leave the ground, if
vekshin1

Answer:

The component form of the vector that represents the velocity of the airplane is (74.1 i , \ 11.73j)\ mph

Step-by-step explanation:

Given;

velocity of the airplane, v = 75 mph

direction of the plane, θ = 9°

The vertical component of the velocity is given by;

V_y = vsin\theta\\\\V_y = (75)(sin \ 9^0)\\\\V_y = 11.73 \ mph

The horizontal component of the velocity is given by;

V_x = vcos \theta\\\\V_x = (75)(cos9^0)\\\\V_x = 74.1 \ mph

Therefore, the component form of the vector that represents the velocity of the airplane is given as;

(V_x , \ V_y) = (74.1 , \ 11.73)\ mph

3 0
3 years ago
Use the intercepts of the following quadratic curve to find its graph.y = -1/2x^2 -3/2x+2
Solnce55 [7]

The correct graph is fourth option

Explanation:\begin{gathered} \text{The quadratic function:} \\ \text{y = }\frac{-1}{2}x^2\text{ - }\frac{3}{2}x\text{ + 2} \end{gathered}

Using the intercepts: we have x-intercept and y-intercept

To get x intercept, we will equate the function to zero. That is y = 0

\begin{gathered} 0\text{ = }\frac{-1}{2}x^2\text{ - }\frac{3}{2}x\text{ + 2} \\ mu\text{ltiply through by 2:} \\ 0=-x^2\text{ - 3x + 4} \\ x^2\text{ + 3x - 4 = 0} \\ x^2\text{ - x + 4x - 4 = 0} \\ x(x\text{- 1) +4(x - 1) = 0} \\ (x\text{ + 4)(x - 1) = 0} \\ x+4\text{ = 0 or x - 1 = 0} \\ x\text{ = -4 or x = 1} \end{gathered}

x intercepts are x = -4 and x = 1

This means the line will cross the x axis at two points: x = -4 and x = 1

To get y-intercept, we will equate x to zero:

\begin{gathered} \text{y = }\frac{-1}{2}(0)^2\text{ - }\frac{3}{2}(0)\text{ + 2} \\ y\text{ = 0 - 0 + 2} \\ y\text{ = 2} \end{gathered}

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This means the line will cross the y axis at y = 2

The correct graph is fourth option

8 0
1 year ago
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Murrr4er [49]
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3 years ago
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3 years ago
Read 2 more answers
Help me with this question please
Finger [1]

a) 1,04

b) 160*0,94=150,4

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

P.S. Hello from Russia

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3 years ago
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