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2 years ago

12

One way to increase acceleration is by

1 answer:

Arlecino [84]2 years ago

4 0

Answer:

D. Increasing both force and mass equally

Step-by-step explanation:

I had a question just like this and I answered it correctly, so I hope this helps.

You might be interested in

Show that if X is a geometric random variable with parameter p, then

Lubov Fominskaja [6]

Answer:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

Step-by-step explanation:

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number os trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

In order to find the expected value E(1/X) we need to find this sum:

$E(X)=\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}$

Lets consider the following series:

$\sum_{k=1}^{\infty} b^{k-1}$

And let's assume that this series is a power series with b a number between (0,1). If we apply integration of this series we have this:

$\int_{0}^b \sum_{k=1}^{\infty} r^{k-1}=\sum_{k=1}^{\infty} \int_{0}^b r^{k-1} dt=\sum_{k=1}^{\infty} \frac{b^k}{k}$ (a)

On the last step we assume that $0\leq r\leq b$ and $\sum_{k=1}^{\infty} r^{k-1}=\frac{1}{1-r}$ , then the integral on the left part of equation (a) would be 1. And we have:

$\int_{0}^b \frac{1}{1-r}dr=-ln(1-b)$

And for the next step we have:

$\sum_{k=1}^{\infty} \frac{b^{k-1}}{k}=\frac{1}{b}\sum_{k=1}^{\infty}\frac{b^k}{k}=-\frac{ln(1-b)}{b}$

And with this we have the requiered proof.

And since $b=1-p$ we have that:

$\sum_{k=1}^{\infty} \frac{p(1-p)^{k-1}}{k}=-\frac{p ln p}{1-p}$

4 0

3 years ago

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

zaharov [31]

After 6 years the investment is $5555.88

Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

The formula used to find future value is:

$A(t)=P(1+\frac{r}{n})^{nt}$

where A(t) = Accumulated amount

P = Principal Amount

r = annual rate

t= time

n= compounding periods per year

We are given:

P = $3600

r = 7.5 %

t = 6

n = 1

Putting values in formula:

$A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88$

So, After 6 years the investment is $5555.88

Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

#learnwithBrainly

8 0

3 years ago

Tori wrote the question for the area of the parallelogram 220.44 equals 16.7 what is the height of the parallelogram

AnnyKZ [126]

Area of parallelogram = base x height

220.44 = 16.7 x height
height = 220.44 ÷ 16.7
height = 13.2 units

Answer: 13.2 units

8 0

2 years ago

Given f (g (x)) = x + 4 and f (x) = 3x + 5, find g (x).

JulijaS [17]

Answer:

g(x) = $\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}$

Step-by-step explanation:

f(x) = 3x + 5

f[g(x)] = 3[g(x)] + 5

⇒ 3[g(x)] + 5 = x + 4

⇒ 3[g(x)] = x + 4 - 5

⇒ 3[g(x)] = x - 1

⇒ g(x) = $\frac{1}{3}(x - 1) = \frac{x}{3} - \frac{1}{3}$

5 0

2 years ago

What is the answer For -6k Plus 7K

Furkat [3]

-6k+7k equals 1k.................................

8 0

2 years ago