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Naddika [18.5K]
3 years ago
12

In the diagram below, which pair of angles is complementary?

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0

Answer:

/2 and /4 because angle 1 is 90

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Htdtdeyt5ey5jed6yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuurrrrrrrrrrrrrrrrrrrrrrrrrr
raketka [301]

Answer: ok LOL thx XD

Step-by-step explanation: BRAINLIEST PLS

8 0
3 years ago
The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
3 years ago
A cup of coffee at 85 degrees Celsius is placed in a room at 25 degrees Celsius. Suppose that the coffee cools at a rate of 5 de
bezimeni [28]

Answer: k = - 6.6667

Step-by-step explanation:

this is quite very simple to begin. I would encourage you take other practice questions similar to help with understanding it.

let us begin.

Given that ;

dT/dt = k ( Tm - T)       where Tm is the temp of the medium

dT/dt = 5 degrees Celsius per minute    when T = 70

so we have that, 5 = k ( 25 - 70)

remember to convert 5 degree celsius per minute to seconds

we have that;

5*60(sec) = k ( 25 - 70)  

k = 5*60 / ( 25 - 70)

k = - 6.6667

note K is negative because we consider it for cooling process  (temp decreasing).

cheers i hope this helps!!!

3 0
3 years ago
BRAINLIEST!! NEED AN ANSWER ASAP!! HELPP
Nata [24]
No; a range value has two domain values.
8 0
3 years ago
Read 2 more answers
What is the simplified form of
umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0
3 years ago
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