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ludmilkaskok [199]
4 years ago
7

It costs $5 for an adult and $2 for a student to visit the National Botanical Gardens. Adults can be members of the Botanical so

ciety and can visit for free. A group of 30 adults and students visited the gardens. Five were members and it cost the group $104. How many students
Mathematics
2 answers:
Kryger [21]4 years ago
6 0

Answer:

30 students!!!!?????

HACTEHA [7]4 years ago
3 0
Answer: There are 2 students

Explanation: Each adult is equal to 5$ so If you divide 104$ by 5$ and only 20 numbers of 5 can fit in 104, and so your left with the number 4 and since each student it equal to 2 dollars that would mean 4 divided by 2, and the answer to that would be 2.

Hopes this helps mate :)
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If you horizontally stretch the quadratic parent function f(x) = x^2 by a factor of 4 what’s the equation of the new function
alisha [4.7K]
F'(x)=(x/4)^2 or (x^2)/16
3 0
3 years ago
Read 2 more answers
consider the series ∑n=1[infinity]4n 2. let sn=∑i=1n4i 2 be the n-th partial sum; that is the sum of the first n terms of the se
Semenov [28]

Answer:

Step-by-step explanation:

4 0
2 years ago
How do you do this pleaseee whel Mee
Rufina [12.5K]
I would use simultaneous equations to do this.
let the greater number be y and the smaller be z.
so,
y - z = 2452. we call this formula 1.
y = 5z. this is formula 2.
since formula 2 directly already tells you what is y, we don't need to modify it, we can directly sub it into formula 1.
so now we get,
5z - z = 2452.
4z = 2452
z = 613
great, now we have z, just sub z = 613 into formula 2.
y = 5 x 613
y = 3065
now we have both numbers and we just add them together for the sum.
613 + 3065 = 3678
so I think the answer is 3678.
3 0
3 years ago
Using the attached link below.
Serhud [2]

\text{Use the Pythagorean theorem:}\\\\r-hypotenuse\\\\r^2=7^2+5^2\\\\r^2=49+25\\\\r^2=74\to r=\sqrt{74}

\sin=\dfrac{opposite}{hypotenuse}\\\\\cos=\dfrac{adjacent}{hypotenuse}\\\\\tan=\dfrac{opposite}{adjacent}\\\\\cot=\dfrac{adjacent}{opposite}\\\\\text{We have}\\\\for\ the\ angle\ y:\\\text{opposite = 7}\\\text{adjacent = 5}\\\text{hypotenuse = }\ \sqrt{74}\\\\for\ the\ angle\ x:\\\text{opposite = 5}\\\text{adjacent = 7}\\\text{hypotenuse = }\ \sqrt{74}

\csc x=\dfrac{1}{\sin x}\\\\\sec x=\dfrac{1}{\cos x}

A.\\\\\sin x=\dfrac{5}{\sqrt{74}}=\dfrac{5\sqrt{74}}{74}\\\\\csc y=\dfrac{1}{\frac{7}{\sqrt{74}}}=\dfrac{\sqrt{74}}{7}\\\\B.\\\\\tan x=\dfrac{5}{7}\\\\\cot y=\dfrc{5}{7}\\\\C.\\\\\cos x=\dfrac{7}{\sqrt{74}}=\dfrac{7\sqrt{74}}{7}\\\\\sec y=\dfrac{1}{\frac{5}{\sqrt{74}}}=\dfrac{\sqrt{74}}{5}

D.\\\sin\theta=\dfrac{2}{3}\\\\\sin^2\theta+\cos^2\theta=1\to\left(\dfrac{2}{3}\right)^2+\cos^2\theta=1\\\\\dfrac{4}{9}+\cos^2\theta=1\qquad\text{subtract}\ \dfrac{4}{9}\ \text{from both sides}\\\\\cos^2\theta=\dfrac{5}{9}\to\cos\theta=\sqrt{\dfrac{5}{9}}\to\cos\theta=\dfrac{\sqrt5}{3}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\to\tan\theta=\dfrac{\frac{2}{3}}{\frac{\sqrt5}{3}}=\dfrac{2}{3}\cdot\dfrac{3}{\sqrt5}=\dfrac{2}{\sqrt5}=\dfrac{3\sqrt5}{5}

6 0
3 years ago
Use all 4 operations and at least one exponent to write and expression that has a value of 10
Yuki888 [10]

5+5=10

15-5=10

5x2=10

20/2=10

10^1 (10 to the power of 1) or 0.1^-1 (0.1 to the power of -1)

7 0
3 years ago
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