Question

The graph of f(x)=2x^3+x^2-4x-2 is shown. How many of the roots of f(x) are rational

Answer 1

We can one theorem to help us find rational roots of this polynomial.

2x^3 + x^2 - 4x - 2

We'll use Descartes' rule of signs.

Because there is 1 sign change, 1 of the 3 roots will be positive.

Now we can make the value of x -1 to see how many negative roots there will be.

-2  + 1 + 4 - 2

There are 2 sign changes, so we know there will be 2 negative roots.

Because of this, we should have 3 real, rational roots.

Answer 2

Answer:

The answer is 1

I don't know the step-by-step explanation

Step-by-step explanation: