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djyliett [7]
3 years ago
13

What is... X/2 - 13 = 1

Mathematics
1 answer:
kow [346]3 years ago
5 0
X ÷ 2 - 13 = 1
Write the division as a fraction
\frac{1}{2}x - 13 = 1
Multiple both sides of the equation by 2
2 \times  \frac{1}{2}x  \times  - 2 \times 13 = 12
Reduce the number with greatest common divisor 2
x - 2 \times 3 = 2
Multiply the numbers
- 2 \times 13
Then u will have
x - 26 = 2
Move constant to the right by adding its opposite sides
x - 26 + 26 = 2 + 26
Eliminate the opposites
- 26 + 26
Then you have
x = 2 + 26
Add the numbers
x = 28

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Which points are on the graph of g(x)=(1/5)x<br><br> Select EACH CORRECT ANSWER
sdas [7]

If a point is on the graph of the exponential equation then it should be true when you solve.


g(x) = (1/5)^x

y = (1/5)^x


1/125 = (1/5)^3

cbrt(1/125) = 1/5

.2 = 1/5

.2 = .2 YES


5 = (1/5)^-1

5 = 5 YES


1/25 = (1/5)^-2

-2root(1/25) = 1/5

5 = 1/5 NO


0 = (1/5)^1

0 = .2 NO


The correct answers are <em>A and B</em>.

6 0
3 years ago
Read 2 more answers
An antelope can run at a speed of 42 miles per hour.How many feet per second is tgis?
coldgirl [10]
 An antelope can run at a speed of 42 miles per hour.How many feet per second is this?
Answer:61.6 feet per second.
5 0
4 years ago
A principal of $3700n is invested at 5.25 interest, compounded annually. How much will the investment be worth after 12
Degger [83]

Answer:

$6837

Step-by-step explanation:

It works well to follow directions, using the calculator that is provided for you. I don't have access to that calculator, so have used my own. It says the investment has a future value after 12 years of $6837.

3 0
3 years ago
Plz I need the answer
alexandr1967 [171]
The answer is 5 inches
5 0
3 years ago
The manager of a national park determines that the park can sustain 81 coyotes. The manager assumes that the rate of change of t
Katena32 [7]

Answer:

N(T) = \frac{81*40*e^{1.075t}}}{81 + 40*(e^{1.075t} - 1)}

Step-by-step explanation:

This problem can be solved by the logistic equation of populations, that is:

N(t) = \frac{KN_{0}e^{rt}}}{K + N_{0}(e^{rt} - 1)}

In which K is the carrying capacity of the population, N_{0} is the initial population, r is the decimal growth rate and t is the period of time.

In this problem, we have that:

When t = 0, the population is 40: This means that N_{0} = 40.

The manager of a national park determines that the park can sustain 81 coyotes. This means that K = 81.

When t = 1, the population has increased to 60. This means that N(1) = 60.

To write the equation, we have to find the value of r.

N(t) = \frac{KN_{0}e^{rt}}}{K + N_{0}(e^{rt} - 1)}

60 = \frac{81*40*e^{r}}}{81 + 40*(e^{r} - 1)}

60*(41 + 40e^{r}) = 3240e^{r}

2460 + 2400e^{r} = 3240e^{r}

840e^{r} = 2460

e^{r} = 2.93

Now we apply ln to both sides, and:

r = 1.075

The answer is:

N(T) = \frac{81*40*e^{1.075t}}}{81 + 40*(e^{1.075t} - 1)}

8 0
4 years ago
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