Ask question

Ask question

All categories

3 years ago

13

What is... X/2 - 13 = 1

1 answer:

kow [346]3 years ago

5 0

X ÷ 2 - 13 = 1
Write the division as a fraction
$\frac{1}{2}x - 13 = 1$
Multiple both sides of the equation by 2
$2 \times \frac{1}{2}x \times - 2 \times 13 = 12$
Reduce the number with greatest common divisor 2
$x - 2 \times 3 = 2$
Multiply the numbers
$- 2 \times 13$
Then u will have
$x - 26 = 2$
Move constant to the right by adding its opposite sides
$x - 26 + 26 = 2 + 26$
Eliminate the opposites
$- 26 + 26$
Then you have
$x = 2 + 26$
Add the numbers
$x = 28$

You might be interested in

Tiago tem uma extensa coleção de livros ele os deixa organizados em uma estante, sparados por gênero. seu gênero favorito, suspe

Andreyy89

Guys help me I’m stuck in this question also it’s in my homework

6 0

3 years ago

IQ scores are measured with a test designed so that the mean is 116 and the standard deviation is 16. Consider the group of IQ s

butalik [34]

Answer:

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 116, \sigma = 16$

What are the z scores that separate the unusual IQ scores from those that are usual?

If Z<-2 or Z > 2, the IQ score is unusual.

So the z-scores that separate the unusual IQ scores from those that are usual are Z = -2 and Z = 2.

What are the IQ scores that separate the unusual IQ scores from those that are usual?

Those IQ scores are X when Z = -2 and X when Z = 2. So

Z = -2

$Z = \frac{X - \mu}{\sigma}$

$-2 = \frac{X - 116}{16}$

$X - 116 = -2*16$

$X = 84$

Z = 2

$Z = \frac{X - \mu}{\sigma}$

$2 = \frac{X - 116}{16}$

$X - 116 = 2*16$

$X = 148$

The IQ scores that separate the unusual IQ scores from those that are usual are 84 and 148.

8 0

2 years ago

Read 2 more answers

How much will a person to a 13.5 pounds of bananas at a price of $2.12 per pound

Paraphin [41]

The answer is 28.62 hope this helps can I get thanks and 5 stars plz?

4 0

3 years ago

Read 2 more answers

Calculate the total cost of an item bought at a negotiated price of $15,640 and a $2,500 trade-in allowance. The sales tax is 7.

mylen [45]

Answer:

B. $14352.08

Step-by-step explanation:

Let us find cost of item after 7.2% of sales tax. The cost of item after 7.2% of sales tax will be equal to 15640 plus 7.2% of 15640.

$\text{The cost of item after sales tax}=15640+(\frac{7.2}{100}\times 15640)$

$\text{The cost of item after sales tax}=15640+(0.072\times 15640)$

$\text{The cost of item after sales tax}=15640+1126.08$

$\text{The cost of item after sales tax}=16766.08$

Therefore the cost of item after 7.2% of sales tax will be $16766.08.

Now let us add registration fee to the cost of item.

$\text{The cost of item after registration fee}=16766.08+86$

$\text{The cost of item after registration fee}=16852.08$

Now let us subtract $2500 trade allowance to find the total cost of the item.

$\text{The total cost of item}=16852.08-2500$

$\text{The total cost of item}=14352.08$

Therefore, the total cost of item will be $14352.08 and option B is the correct choice.

6 0

2 years ago

A bag contains equal numbers of green marbles and blue marbles. You can divide all of the green marbles into groups of 12 and al

Furkat [3]

Answer: 48

Step-by-step explanation:

We need to find the least common multiple of 12 and 16.

Finding the prime factorizations of 12 and 16,

$12=2^{2} \times 3\\\\16=2^{4}$

Thus, the least common multiple is $2^{4} \times 3=\boxed{48}$

6 0

1 year ago