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jenyasd209 [6]
2 years ago
15

Please I need to know if its true or false please lmk!!!​

Mathematics
2 answers:
Papessa [141]2 years ago
7 0

Answer:

False

Step-by-step explanation:

<u>According to the complex conjugate root theorem:</u>

if a complex number is a root of a polynomial, its conjugate is also the root of the polynomial

We are given all the roots of the polynomial and there is only one complex root

Since according to the complex conjugate root theorem, there can be either none or at least 2 complex roots of a polynomial

We can say that this set of roots of a polynomial is incorrect

prisoha [69]2 years ago
7 0

Answer:

False

Step-by-step explanation:

As the other guy/gal said,

It can only have 2 or 0 roots.

As it has 5 roots,

The statement is false.

I hope this helps you :)

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The Cool Company determines that the supply function for its basic air conditioning unit is S(p) = 10 + 0.002p3 and that its dem
Radda [10]

Answer: At $21.85, the supply will equal to demand.

Step-by-step explanation:

Since we have given that

Demand function is given by

D(p) = 50 - 0.04p^2, \text{where p is the price.}

Supply function is given by

S(p) = 10 + 0.002p^3

According to question, we need to find the price for which the supply equals the demand, i.e. Equilibrium price and quantity.

D(p)=S(p)\\\\50-0.04p^2=10+0.002p^3\\\\50-10=0.002p^3+0.04p^2\\\\40=\frac{2}{1000}p^3+\frac{4}{100}p^2\\\\40=\frac{2}{100}p^2(\frac{1}{10}p+2)\\\\\frac{40\times 100}{2}=p^2(\frac{1p+20}{2})\\\\\mathrm{The\:Newton-Raphson\:method\:uses\:an\:iterative\:process\:to\:approach\:one\:root\:of\:a\:function}\\\\p\approx \:21.85861\dots

So, at $21.85, the supply will equal to demand.

3 0
3 years ago
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A furniture rental company charges a fixed amount plus a fee based on the number of days for which the furniture is rented. The
baherus [9]
The fixed amount is the amount charged for 0 days' rental. The ordered pair (0, 80) tells you it is $80.
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How can the statement below be rewritten as a conditional statement in if-then form?
Irina-Kira [14]

Answer:

<h2>If two angles measures 180 degrees, then they form a linear pair.</h2>

Step-by-step explanation:

The conditional statement should be this way, because after the word ''if'', should be placed the condition, and after the word ''then'', should be the consequence.

5 0
3 years ago
A random sample of n = 64 observations is drawn from a population with a mean equal to 20 and standard deviation equal to 16. (G
dezoksy [38]

Answer:

a) The mean of a sampling distribution of \\ \overline{x} is \\ \mu_{\overline{x}} = \mu = 20. The standard deviation is \\ \frac{\sigma}{\sqrt{n}} = \frac{16}{\sqrt{64}}=2.

b) The standard normal z-score corresponding to a value of \\ \overline{x} = 16 is \\ Z = -2.

c) The standard normal z-score corresponding to a value of \\ \overline{x} = 23 is \\ Z = 1.5.

d) The probability \\ P(\overline{x}.

e) The probability \\ P(\overline{x}>23) = 1 - P(Z.

f)  \\ P(16 < \overline{x} < 23) = P(-2 < Z < 1.5) = P(Z.

Step-by-step explanation:

We are dealing here with the concept of <em>a sampling distribution</em>, that is, the distribution of the sample means \\ \overline{x}.

We know that for this kind of distribution we need, at least, that the sample size must be \\ n \geq 30 observations, to establish that:

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})

In words, the distribution of the sample means follows, approximately, a <em>normal distribution</em> with mean, \mu, and standard deviation (called <em>standard error</em>), \\ \frac{\sigma}{\sqrt{n}}.

The number of observations is n = 64.

We need also to remember that the random variable Z follows a <em>standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1.

\\ Z \sim N(0, 1)

The variable Z is

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}} [1]

With all this information, we can solve the questions.

Part a

The mean of a sampling distribution of \\ \overline{x} is the population mean \\ \mu = 20 or \\ \mu_{\overline{x}} = \mu = 20.

The standard deviation is the population standard deviation \\ \sigma = 16 divided by the root square of n, that is, the number of observations of the sample. Thus, \\ \frac{\sigma}{\sqrt{n}} = \frac{16}{\sqrt{64}}=2.

Part b

We are dealing here with a <em>random sample</em>. The z-score for the sampling distribution of \\ \overline{x} is given by [1]. Then

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{16 - 20}{\frac{16}{\sqrt{64}}}

\\ Z = \frac{-4}{\frac{16}{8}}

\\ Z = \frac{-4}{2}

\\ Z = -2

Then, the <em>standard normal z-score</em> corresponding to a value of \\ \overline{x} = 16 is \\ Z = -2.

Part c

We can follow the same procedure as before. Then

\\ Z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{23 - 20}{\frac{16}{\sqrt{64}}}

\\ Z = \frac{3}{\frac{16}{8}}

\\ Z = \frac{3}{2}

\\ Z = 1.5

As a result, the <em>standard normal z-score</em> corresponding to a value of \\ \overline{x} = 23 is \\ Z = 1.5.

Part d

Since we know from [1] that the random variable follows a <em>standard normal distribution</em>, we can consult the <em>cumulative standard normal table</em> for the corresponding \\ \overline{x} already calculated. This table is available in Statistics textbooks and on the Internet. We can also use statistical packages and even spreadsheets or calculators to find this probability.

The corresponding value is Z = -2, that is, it is <em>two standard units</em> <em>below</em> the mean (because of the <em>negative</em> value). Then, consulting the mentioned table, the corresponding cumulative probability for Z = -2 is \\ P(Z.

Therefore, the probability \\ P(\overline{x}.

Part e

We can follow a similar way than the previous step.

\\ P(\overline{x} > 23) = P(Z > 1.5)

For \\ P(Z > 1.5) using the <em>cumulative standard normal table</em>, we can find this probability knowing that

\\ P(Z1.5) = 1

\\ P(Z>1.5) = 1 - P(Z

Thus

\\ P(Z>1.5) = 1 - 0.9332

\\ P(Z>1.5) = 0.0668

Therefore, the probability \\ P(\overline{x}>23) = 1 - P(Z.

Part f

This probability is \\ P(\overline{x} > 16) and \\ P(\overline{x} < 23).

For finding this, we need to subtract the cumulative probabilities for \\ P(\overline{x} < 16) and \\ P(\overline{x} < 23)

Using the previous <em>standardized values</em> for them, we have from <em>Part d</em>:

\\ P(\overline{x}

We know from <em>Part e</em> that

\\ P(\overline{x} > 23) = P(Z>1.5) = 1 - P(Z

\\ P(\overline{x} < 23) = P(Z1.5)

\\ P(\overline{x} < 23) = P(Z

\\ P(\overline{x} < 23) = P(Z

Therefore, \\ P(16 < \overline{x} < 23) = P(-2 < Z < 1.5) = P(Z.

5 0
3 years ago
Solve the system of equations {3x-y=10, -x y=12} for Y
Novosadov [1.4K]
3x - y = 10 . . . (1)
-x + y = 12 . . . (2)

(1) + (2) => 2x = 22 => x = 22/2 = 11

From 2, -11 + y = 12 => y = 12 + 11 = 23
5 0
3 years ago
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