3(-2 - x) in simplified expression

Mathematics

2 answers:

egoroff_w [7]3 years ago

5 0

Answer:

-6-3x

Step-by-step explanation:

Drupady [299]3 years ago

4 0

Answer: -6-3x

Step-by-step explanation:

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The line with the slope m=-7 and passes through (-4,6)

ss7ja [257]

Answer:

y=-7x-22

Step-by-step explanation:

y-y1=m(x-x1)

y-6=-7(x-(-4))

y-6=-7(x+4)

y=-7x-28+6

y=-7x-22

Please mark me as Brainliest if you're satisfied with the answer.

6 0

2 years ago

If <img src="https://tex.z-dn.net/?f=log_8%20N%20%3D%20%5Cfrac%7Br%7D%7B2%7D%20%5C%3A%20%2C%20%5C%3A%20log_2%282N%29%3D%205%5C%3

Rudik [331]

Answer:

N = 2 $\frac{3r}{2}$

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The line that contains the point Q( 1, -2) and is parallel to the line whose equation is

Triss [41]

Let's call this line y=mx+C, whereby 'm' will be its gradient and 'C' will be its constant.

If this line is parallel to the line you've just mentioned, it will have a gradient 2/3. We know this, because when we re-arrange the equation you've given us, we get...

$y-4=\frac { 2 }{ 3 } \left( x-3 \right) \\ \\ y-4=\frac { 2 }{ 3 } x-2\\ \\ y=\frac { 2 }{ 3 } x-2+4\\ \\ y=\frac { 2 }{ 3 } x+2$

So, at the moment, our parallel line looks like this...

y=(2/3)*x + C

However, you mentioned that this line passes through the point Q(1, -2). If this is the case, for the line (almost complete) above, when x=1, y=-2. With this information, we can figure out the constant of the line we want to find.

-2=(2/3)*(1) + C

Therefore:

C = - 2 - (2/3)

C = - 6/3 - 2/3

C = - 8/3

This means that the line you are looking for is:

y=(2/3)*x - (8/3)

Let's find out if this is truly the case with a handy graphing app... Well, it turns out that I'm correct.