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pashok25 [27]
3 years ago
11

Verify which of the following are identities.

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

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Q1.
Alinara [238K]

Answer:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers

Step-by-step explanation:

In order to find the smallest number of units that would be possible to buy, find the least common multiple between the number of units in each box:

12\ \ 10\ \ 6\ |2\\6\ \ \ \ 5\ \ \ 3\ |2\\3\ \ \ \ 5\ \ \ 3\ |3\\1\ \ \ \ 5\ \ \ 1\ |5\\1\ \ \ \ 1\ \ \ 1\ | = 2*2*3*5=60

The number of boxes required for each item to get 60 units is:

d=\frac{60}{12} = 5\ boxes \\p=\frac{60}{10} = 6\ boxes \\r=\frac{60}{6} = 10\ boxes

the smallest number of boxes of each item he could buy is:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers

8 0
3 years ago
On an alien planet with no atmosphere, acceleration due to gravity is given by g = 12m/s^2. A cannonball is launched from the or
almond37 [142]

Answer:

a) \vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j, b) \theta = \frac{\pi}{4}, c) y_{max} = 84.375\,m, t = 3.75\,s.

Step-by-step explanation:

a) The function in terms of time and the inital angle measured from the horizontal is:

\vec r (t) = [(v_{o}\cdot \cos \theta)\cdot t]\cdot i + \left[(v_{o}\cdot \sin \theta)\cdot t -\frac{1}{2}\cdot g \cdot t^{2} \right]\cdot j

The particular expression for the cannonball is:

\vec r (t) = \left[(90\cdot \cos \theta)\cdot t \right]\cdot i + \left[(90\cdot \sin \theta)\cdot t -6\cdot t^{2} \right]\cdot j

b) The components of the position of the cannonball before hitting the ground is:

x = (90\cdot \cos \theta)\cdot t

0 = 90\cdot \sin \theta - 6\cdot t

After a quick substitution and some algebraic and trigonometric handling, the following expression is found:

0 = 90\cdot \sin \theta - 6\cdot \left(\frac{x}{90\cdot \cos \theta}  \right)

0 = 8100\cdot \sin \theta \cdot \cos \theta - 6\cdot x

0 = 4050\cdot \sin 2\theta - 6\cdot x

6\cdot x = 4050\cdot \sin 2\theta

x = 675\cdot \sin 2\theta

The angle for a maximum horizontal distance is determined by deriving the function, equalizing the resulting formula to zero and finding the angle:

\frac{dx}{d\theta} = 1350\cdot \cos 2\theta

1350\cdot \cos 2\theta = 0

\cos 2\theta = 0

2\theta = \frac{\pi}{2}

\theta = \frac{\pi}{4}

Now, it is required to demonstrate that critical point leads to a maximum. The second derivative is:

\frac{d^{2}x}{d\theta^{2}} = -2700\cdot \sin 2\theta

\frac{d^{2}x}{d\theta^{2}} = -2700

Which demonstrates the existence of the maximum associated with the critical point found before.

c) The equation for the vertical component of position is:

y = 45\cdot t - 6\cdot t^{2}

The maximum height can be found by deriving the previous expression, which is equalized to zero and critical values are found afterwards:

\frac{dy}{dt} = 45 - 12\cdot t

45-12\cdot t = 0

t = \frac{45}{12}

t = 3.75\,s

Now, the second derivative is used to check if such solution leads to a maximum:

\frac{d^{2}y}{dt^{2}} = -12

Which demonstrates the assumption.

The maximum height reached by the cannonball is:

y_{max} = 45\cdot (3.75\,s)-6\cdot (3.75\,s)^{2}

y_{max} = 84.375\,m

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3 years ago
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gregori [183]

Answer:

c

Step-by-step explanation:

because on the chart is says 19% under burgers for teachers.

Tell me if it is right.

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2 years ago
Identify a sequence of transformation that maps triangle ABC onto triangle A"B"C" in the image below.
Vladimir79 [104]
I'd go with: D. clockwise 90 rotation; reduction 

(Hope I helped :D
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The answer is 420 people
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3 years ago
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