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pashok25 [27]
3 years ago
11

Verify which of the following are identities.

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

<u>Note that </u>

\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot    \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

8\sec(\theta)=8\csc(\theta)

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

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Kindly solve this question 6 too !!
Shkiper50 [21]

Answer:

x=1

Step-by-step explanation:

~~~~~x = \dfrac{1}{2 - \dfrac 1{2-\dfrac{1}{2-x}}}\\\\\\\implies x = \dfrac{1}{2 - \dfrac 1{\dfrac{4-2x-1}{2-x}}}\\\\\\\implies x= \dfrac{1}{2 - \dfrac{2-x}{3-2x}}\\\\\\\implies x = \dfrac{1}{\dfrac{6-4x-2+x}{3-2x}}\\\\\\\implies x = \dfrac{3-2x}{4-3x}\\\\\\\implies 4x -3x^2 = 3-2x\\\\\\\implies 3x^2 -4x +3-2x = 0\\\\\\\implies 3x^2 -6x +3 = 0\\\\\\\implies 3(x^2 -2x +1) =0\\\\\\\implies x^2 -2x +1 = 0\\\\\\\implies (x-1)^2 = 0\\\\\\\implies x -1 = 0\\\\\\\implies x = 1

7 0
2 years ago
Evaluate the following numerical expressions. 6 + 23 • 3 =
klasskru [66]

6 + 23(3)

6 + 69

75

Hope this helps! ;)

3 0
3 years ago
Read 2 more answers
Brad is having a party and buys a large cube of cheddar cheese at the market. The cube is 4 inches in height. When Brad gets hom
Naddika [18.5K]

Answer:

32 cubic inches

Step-by-step explanation:

4^3= 64

64/2= 32

3 0
3 years ago
Please Select the best answer from the choices provided
Yuri [45]
The answer is i'm sure B
4 0
3 years ago
Peter is buying office supplies he is able to buy three packages of paper in for staplers for $40 or he is able to buy five pack
Damm [24]

<u>Answer:</u>

Cost of package of paper = 4$

Cost of stapler = 7$

<u>Explanation:</u>

Consider the cost of package of paper = x and that of stapler = y.

Now, we are given that cost of 3 paper packages and 4 staplers = 40$

Hence we get, 3x + 4y = 40 as 1st equation.

we are also given, cost of 5 paper packages and 6 staplers = 62$

Hence, the second equation is 5x + 6y = 62

Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->

15x + 20y = 200

15x + 18y= 186

Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4

which gives the required cost of one paper package = x = 4$

and one stapler = y = 7$

7 0
3 years ago
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