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Y_Kistochka [10]
3 years ago
8

Peter is buying office supplies he is able to buy three packages of paper in for staplers for $40 or he is able to buy five pack

ages of paper and six staplers for $62 how much does a package of paper cost how much does a stapler cost
Mathematics
1 answer:
Damm [24]3 years ago
7 0

<u>Answer:</u>

Cost of package of paper = 4$

Cost of stapler = 7$

<u>Explanation:</u>

Consider the cost of package of paper = x and that of stapler = y.

Now, we are given that cost of 3 paper packages and 4 staplers = 40$

Hence we get, 3x + 4y = 40 as 1st equation.

we are also given, cost of 5 paper packages and 6 staplers = 62$

Hence, the second equation is 5x + 6y = 62

Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->

15x + 20y = 200

15x + 18y= 186

Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4

which gives the required cost of one paper package = x = 4$

and one stapler = y = 7$

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Step-by-step explanation:

x/3-2<4

x/3<6

x<18

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Find the surface area of a cylinder with the following dimensions. Use 3. 14 for $. Round your answer to the nearest
kupik [55]

Answer:

b

Step-by-step explanation:

r=d/2=11.4/2=5.7

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7 0
3 years ago
PLEASE HELP ME NOW URGENT
timama [110]

ANSWER

y   = 3 \pm \sqrt{21}

EXPLANATION

The quadratic equation is:

{y}^{2}  - 6y - 12 = 0

Group variable terms:

{y}^{2}  - 6y = 12

Add the square of half, the coefficient of y to both sides.

{y}^{2}  - 6y  + ( - 3) ^{2} = 12 + ( - 3) ^{2}

{y}^{2}  - 6y  + 9= 12 + 9

The LHS us now a perfect square trinomial:

{(y - 3)}^{2}= 21

Take square root:

y - 3 =  \pm \sqrt{21}

y = 3 \pm \sqrt{21}

The first choice is correct.

8 0
3 years ago
Read 2 more answers
Help please I'm stuck show and explain your work
Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

6(x+4)=20, (x+4) = \frac{20}{6}   = 3.333,

x = 3.333 - 4 = -0.666.

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. \frac{20-4}{6}= \frac{16}{6}  = 2.666,

B. \frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,

C. 20 -6 -4 = 20 - 10 = 10.

D. \frac{20}{6} -4= 3.333 - 4 = -0.666,

E. \frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,

F. (20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.

So the options D, E, and F represent a correct solution to the given equation.

7 0
3 years ago
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