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lbvjy [14]
3 years ago
12

Joshua and his children went into a bakery and he bought $15 worth of donuts and cookies. Each donut costs $1.75 and each cookie

costs $1. He bought a total of 12 donuts and cookies altogether . Determine the number of donuts and the number of cookies that Joshua bought .
Mathematics
2 answers:
Natalija [7]3 years ago
7 0

Answer:

Joshua bought 12 cookies & ABOUT 7 donuts.

Step-by-step explanation:

Mumz [18]3 years ago
4 0

Answer:

The number of donuts bought is 4 while the number of cookies bought is 8

Step-by-step explanation:

Joshua bought donuts and cookies. The cost of each donuts is $1.75 and the cost of each cookies is $1. He bought a total number 12 donuts and cookies altogether. But the number of donuts bought and the number of cookies bought is not given.

Let the number of donuts bought = a

Let the number of cookies bought = b

The total cost of the donuts and cookies bought = $15

The total number of donuts and cookies bought = 12

Therefore,

1.75a + 1b = 15....................................(i)

a + b = 12.............................................(ii)

b = 12 - a

Inserting the value of b in equation (i)

1.75a + 12 - a = 15

1.75a - a = 15 - 12

0.75a = 3

a = 3/0.75

a = 4

Inserting a in equation(ii)

4 + b = 12

b = 12 - 4

b = 8

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3 years ago
Given rectangle QUAD, If DU = 5x - 4 and QP = 2x + 7, then find the length of DU.
ira [324]

Answer:

DU = 86

Step-by-step explanation:

Properties of a rectangle,

- Opposite sides are equal in measure.

- Diagonals of a rectangle are equal.

- Diagonals bisect each other.

In the given rectangle QUAD,

Diagonals AQ and DU bisect each other at P.

AQ = DU

2(QP) = DU [Since, AQ = 2(PQ)]

2(2x + 7) = 5x - 4

4x + 14 = 5x - 4

5x - 4x = 14 + 4

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Since, DU = 5x - 4

DU = 5(18) - 4

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Write the equation, in standard form, of a polynomial of the least degree with integral
Hitman42 [59]

Answer:

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

Explanation:

If the zero is c, the factor is (x-c).

So for zeros of

−

3

,

−

1

3

,

5

, the factors are

(

x

+

3

)

(

x

+

1

3

)

(

x

−

5

)

Let's take a look at the factor

(

x

+

1

3

)

. Using the factor in this form will not result in integer coefficients because

1

3

is not an integer.

Move the

3

in front of the x and leave the

1

in place:

(

3

x

+

1

)

.

When set equal to zero and solved, both

(

x

+

1

3

)

=

0

and

(

3

x

+

1

)

=

0

result in

x

=

−

1

3

.

f

(

x

)

=

(

x

+

3

)

(

3

x

+

1

)

(

x

−

5

)

Multiply the first two factors.

f

(

x

)

=

(

3

x

2

+

10

x

+

3

)

(

x

−

5

)

Multiply/distribute again.

f

(

x

)

=

3

x

3

+

10

x

2

+

3

x

−

15

x

2

−

50

x

−

15

Combine like terms.

f

(

x

)

=

3

x

3

−

5

x

2

−

47

x

−

15

5 0
3 years ago
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