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4 years ago

Multiply 6y(y-21) need help

Mathematics

2 answers:

Lady bird [3.3K]4 years ago

7 0

The answer would be 6y^2-126y

Roman55 [17]4 years ago

5 0

Answer:

6y^2-126y

Step-by-step explanation:

In order to solve this, you would multiply 6y by the numbers in the parenthesis.

6y multiplied by y is 6y^2 and 6y multiplied by 21 is 126y.

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I need help with this problem please help :)

wel

Hello! To find the answer to this, let’s do 6x + 4x = 180. Combine like terms and you get that 10x = 180. Divide each side by 10 in order to get 18. Angle 1 = 108 degrees and Angle 12 = 72 degrees. Odd number angles match each other and even number angles match each other. In this case, 5 has the same angle measurement as 1, which is 108. The answer is D: 108 degrees.

3 0

3 years ago

Learning goal: to understand the rules for computing dot products. let vectors a=(2,1,−4), b=(−3,0,1), and c=(−1,−1,2). part a -

miv72 [106K]

For this case we have the following vectors:
$a = (2,1, -4)

b = (- 3,0,1)

c = (- 1, -1,2)$
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
$a.b = (2,1, -4). (- 3,0,1)

a.b = (2) (- 3) + (1) (0) + (-4) (1)

a.b = - 6 + 0 - 4

a.b = - 10$
Answer:
The product point of the vectors a and b is:
$a.b = - 10$

3 0

4 years ago

Write a cubic function with zeros of -3, -5 and 2

Lady bird [3.3K]

For zeroes of r1,r2,r3, the factors of the function, f(x) are
(x-r1)(x-r2)(x-r3)

zeroes of -3,-5,2
(x-(-3))(x-(-5))(x-2)=
(x+3)(x+5)(x-2)

f(x)=(x+3)(x+5)(x-2)
expanded
f(x)=x³+6x²-x-30

5 0

3 years ago

If (a^x a ^y) - a^z = a^m then express m in terms of x, y and z.

omeli [17]

Answer:

m = x+y-z

Step-by-step explanation:

Given the expression.

(a^x a ^y) ÷ a^z = a^m

We are to express m in terms of x, y and z.

Using the multiplicative law of indices, the expression becomes:

a^{x+y} ÷ a^z = a^m

Applying the division rule in indices

a^{x+y} ÷ a^z = a^{x+y-z}

The equation becomes

a^{x+y-z} = a^m

Cancel out the base and equate the powers as shown:

x+y-z = m

Hence the expression of m in terms of x, y and z is m = x+y-z

8 0

3 years ago

Please help me with this

mylen [45]

Answer: The last option, or D

Step-by-step explanation:

35x−35y+21

8 0

3 years ago