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Sunny_sXe [5.5K]
3 years ago
11

Multiply 6y(y-21) need help

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0
The answer would be 6y^2-126y
Roman55 [17]3 years ago
5 0

Answer:

6y^2-126y

Step-by-step explanation:

In order to solve this, you would multiply 6y by the numbers in the parenthesis.

6y multiplied by y is 6y^2 and 6y multiplied by 21 is 126y.

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Choose the simplified solution(s) to this equation: ?- 128 - 0 18 1642 V128 18/2 Question 33 )​
tatiyna

D is correct answer

±8√2

7 0
2 years ago
The box plots below show student grades on the most recent exam compared to overall grades in a class:
777dan777 [17]

The statement that best describes the information about the medians would be: the class median and exam median are almost the same.

<h3>Median of a Data Set on a Box Plot</h3>
  • The median of any data distribution that is plotted on a box plot is indicated by the vertical line that divides the rectangular box in the box plot.

Thus:

  • The median for class is 84
  • The median for exam is 85.

Therefore, the statement that best describes the information about the medians would be: the class median and exam median are almost the same.

Learn more about Box Plot on:

brainly.com/question/10209877

3 0
2 years ago
PLEASE HELP! I WILL GIVE BRAINLIEST!<br> A<br> B<br> C<br> D<br> E
I am Lyosha [343]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What’s the answer?????
jeka57 [31]
The answer will be narrow
5 0
2 years ago
Since an instant replay system for tennis was introduced at a major​ tournament, men challenged 1406 referee​ calls, with the re
erastova [34]

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for men and women players. The population proportions of men and women challenges for calls would be p1 and p2

P1 - P2 = difference in the proportion of men and women challenges for calls.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success(number of complaints)

n represents number of samples

For old dough

x1 = 416

n1 = 1406

P1 = 416/1406 = 0.3

For new dough,

x2 = 217

n2 = 778

P2 = 217/778 = 0.28

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (416 + 217)/(1406 + 778) = 0.29

1 - pc = 1 - 0.29 = 0.71

z = (P1 - P2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.3 - 0.28)/√(0.29)(0.71)(1/1406 + 1/778) = 0.02/√0.00553857907

z = 0.99

Since it is a two tailed test, the curve is symmetrical. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score to the left of 0.99 is 1 - 0.84 = 0.16

We would double this area to include the area in the left tail of z = - 0.99 Thus

p = 0.16 × 2 = 0.32

Since 0.1 < 0.5, we would accept the null hypothesis.

p value = 0.337

Since 0.05 < 0.32, we would accept the null hypothesis

7 0
3 years ago
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