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1 answer:
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2><h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2><h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2><h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
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Answer:
An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:
Step-by-step explanation:
Given the points
- (-4,1)
- (4,3)
Finding the slope between the points (-4,1) and (4,3)
Refine
Point slope form:
where
- m is the slope of the line
- (x₁, y₁) is the point
in our case,
- m = 1/4
- (x₁, y₁) = (-4,1)
substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.
Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be: