Please help ASAP !!! Thank you !
1 answer:
<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2><h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2><h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2><h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
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The function g(x) = 3x-4 is a linear function. Therefore the inverse does exist (which is also linear)
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The answer is choice D
Because we have an inverse, this means we can use the rule
Replace x with 13
The answer is choice D
Answer:
6 + 3 + 2
+
Step-by-step explanation:
Using the rule of radicals
×
⇔
Given
(3 + )(2 +
)
Each term in the second factor is multiplied by each term in the first factor, that is
3(2 + ) +
(2 +
) ← distribute both parenthesis
= 6 + 3 + 2
+