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Margarita [4]
3 years ago
14

What are the formulas for exponential growth and decay?

Mathematics
2 answers:
fiasKO [112]3 years ago
5 0

Answer: The formula for exponential growth is y = a(1 + r)^x, and the formula for exponential decay is y = a(1 - r)^x, with r being the rate of growth/decay. :)

Natalka [10]3 years ago
3 0

Answer: I don’t really remember the answer but I will edit my answer later and answer this question correctly

Step-by-step explanation:

You might be interested in
For what value of h is 24=h/10-6​
faltersainse [42]

Answer:

h=3

Step-by-step explanation:

h/10 -6 =24

+6 to each side

h/10=30

divide each side by 10

h=3

5 0
3 years ago
Need Help, Trying To Finish .
hammer [34]
Answer:

8

Steps:

Plug in 2 for x in h(x)

h(2) = -(2)^2 + 6 * 2

h(2) = -4 + 12

h(2) = 8
3 0
3 years ago
PLS HELP
fenix001 [56]

Answer:

April

Step-by-step explanation:

To solve, you find the maximum of the polynomial function. You can do this by either graphing or plugging in the values in a T chart.

I graphed the function, provided down below.

As you can see, the highest value in the graph is the middle most point, aka (4,1). Count down the months of the year to 4, and you'll find that April is the 4th month of the year.

6 0
3 years ago
A bag has 16 blue marbles and 14 red marbles. John will randomly select 1 marble from the bag. What is the probability that he w
Lapatulllka [165]

Answer:

46.66% chance of red marble

Step-by-step explanation:

Red Marbles / Total Marbles gives you the percent

14 / 30 = 46.66%

8 0
2 years ago
#2: Solve the linear system below using the elimination method. Type your
MariettaO [177]

The given linear system is:

\displaystyle \left \{ {{5x+7y=33} \atop {11x+7y=39}} \right.

The question is asking to solve using elimination. When eliminating, you can either eliminate x or y. In this system, y is much easier to eliminate. The y variable in both equations are 7y. To eliminate, one of them has to be negative, so multiply one of the equations by -1.

I will be multiplying the second equation by -1.

\displaystyle (11x + 7y = 39) \times -1 = -11x-7y=-39

Rewrite the system:

\displaystyle \left \{ {{5x+7y=33} \atop {-11x-7y=-39}} \right.

Subtract:

5x+7y=33\\-11x-7y=-39

5x-11x=33-39\\-6x=-6

Lastly, you need to leave the variable x alone. The variable is currently -6x or -6 times x. To remove it, you need to do the opposite of it, which is dividing by -6.

\displaystyle \frac{-6x}{-6} =\frac{-6}{-6}

\displaystyle x=1

Now that you have the value of x, substitute it into one of the equations to find y. I will be substituting it into the first equation.

5x+7y=33 \rightarrow 5(1)+7y=33

Open the parentheses and multiply:

5+7y=33

Move 5 to the other side to leave the variable alone:

5+7y-5=33-5

You will be subtracting since you're "removing" it by doing the opposite of it.

7y=28

Lastly, divide both sides by 7 to leave y alone.

\displaystyle \frac{7y}{7} =\frac{28}{7}

y=4

\displaystyle (x,y) \rightarrow (1, 4)

The answer is (1, 4).

8 0
2 years ago
Read 2 more answers
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