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Vinil7 [7]
3 years ago
14

Yesterday, it took 40 minutes to drive to school. Today, it took 32 minutes to drive to school. What is your percent of change?

Mathematics
2 answers:
liubo4ka [24]3 years ago
6 0
-20%




















.........................
Citrus2011 [14]3 years ago
4 0

Step-by-step explanation:

decrease by 20%

xxxxxxxx

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Question 1. Please help, What is the measure of ∠D?
erastova [34]

Step-by-step explanation:

It is 28°

Because both triangles FED and ABC are right (converse of pythagorean theorem)

Also the lengths of the side of the triangle ABC is double the lengths of the side of the other triangle

You calculate the measure of the angle ∠A in triangle ABC which is 28° (by calculation)

This will also be the measure of angle D

I'm not sure if it is right but hopefully it will help you.

8 0
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How did you get the five consecutive integer that have a product of 524,160​
a_sh-v [17]
12*13*14*15*16 = 524160

Idk how to get this answer actually. It's just my first guess, and it happened to be right.
7 0
3 years ago
Solve the following literal equations for the specified variable <br> U+ka=ba,for a
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3 years ago
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Vladimir [108]

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3.6

Step-by-step explanation:

7 0
3 years ago
Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe
Stolb23 [73]

Answer:

Step-by-step explanation:

The model N (t), the number of planets found up to time t, as a Poisson process. So, the N (t) has distribution of Poison distribution with parameter (\lambda t)

a)

The mean for a month is, \lambda = \frac{1}{3} per month

E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8

(Here. t = 24)

For Poisson process mean and variance are same,

Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8

 

(Poisson distribution mean and variance equal)

 

The standard deviation of the number of planets is,

\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828

b)

For the Poisson process the intervals between events(finding a new planet) have  independent  exponential  distribution with parameter \lambda. The  sum  of K of these  independent exponential has distribution Gamma (K, \lambda).

From the given information, k = 6 and \lambda =\frac{1}{3}

Calculate the expected value.

E(x)=\frac{\alpha}{\beta}\\\\=\frac{K}{\lambda}\\\\=\frac{6}{\frac{1}{3}}\\\\=18

(Here, \alpha =k and \beta=\lambda)                                                                      

C)

Calculate the probability that she will become eligible for the prize within one year.

Here, 1 year is equal to 12 months.

P(X ≤ 12) = (1/Г  (k)λ^k)(x)^(k-1).(e)^(-x/λ)

=\frac{1}{Г  (6)(\frac{1}{3})^6}(12)^{6-1}e^{-36}\\\\=0.2148696\\=0.2419\\=21.49%

Hence, the required probability is 0.2149 or 21.49%

5 0
3 years ago
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