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Ne4ueva [31]
4 years ago
9

Which expression is equivalent to the following expression? -4(3x + 4)

Mathematics
2 answers:
cricket20 [7]4 years ago
7 0

Answer:

7x

Step-by-step explanation:

Taya2010 [7]4 years ago
3 0

Answer:

-12x - 16

Step-by-step explanation:

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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
Is (ab^2) equivalent to ab^2? Explain.
Zarrin [17]

Answer: yes it is equivalent!

Step-by-step explanation:

all you do is take away the parentheses and then it is the same exact thing!

6 0
3 years ago
Read 2 more answers
Find the
Umnica [9.8K]

Answer:

1. 135 2. 16.875

Step-by-step explanation:

1. 5 x 4.5 x 6 = 135

2. 2.5 x 2.25 x 3 = 16.875

8 0
3 years ago
Parker bought 26.7 feet of cable. He paid $0.60 per foot.  How much did Parker spend on cable?   A. $160.20   B. $44.50   C. $16
Scilla [17]
I think it will be $16.02 
8 0
3 years ago
Read 2 more answers
10.
miv72 [106K]
A. To answer this question, we must consider two inequalities. The first inequality we will construct is regarding the number of tickets sold with respect to capacity. The theater cannot exceed the allotted 200 seats, so this would indicate we would use a less than or equal to inequality. The inequality we would construct to illustrate this using adult and child tickets is x + y <= 200.
The second inequality we will construct is based upon the ticket prices set and the theater’s goal. The problem indicates the theater wants to sell “at least $1,500 worth of tickets...” To create the inequality here, we will create it as follows: 12.5x + 6.25y >= 1,500.
To find the intersection point, we must isolate y. In order to do this, move x to the other side of both inequalities. Inequality 2 can be simplified to y >= -12.5x / 6.25 + 1,500 / 6.25. Graph and identify the solution from there.
8 0
3 years ago
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