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3 years ago

Which statement is true?

Mathematics

2 answers:

BigorU [14]3 years ago

7 0

Answer:

the second option

Step-by-step explanation:

imagine a number line

______________________________________________________

-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7

| | | |

-6.9 -1.2 1.2 6.9

the integer further to to the right is greater

krok68 [10]3 years ago

5 0

Answer:

(B) 1.2 > -6.9

Explanation:

The negative numbers/decimals are always to the left of the 0 on a number line. They are not positive.

The positive numbers are always to the right of the 0 on a number line. They are always greater than negative numbers.

6.9 might be greater than 1.2 if it is a positive number, but if it is a negative number, 1.2 is greater.

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Answer:

$x \geq 4y$

$7.50x+4.75y\leq 125$

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Step-by-step explanation:

Let

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y -----> the number of red rose bushes

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$y > 0$ ----> inequality D

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3 years ago

Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f

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Answer:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

$\hat p=0.64$ estimated proportion of interest

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:

Null hypothesis: $p =0.5$

Alternative hypothesis: $p > 0.5$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info given we got:

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43$

Now we can calculate the p value with the following probability:

$p_v =P(z>2.43)=0.0075 \approx 0.008$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

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