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MaRussiya [10]
3 years ago
13

Problema: Se guarda una moneda antigua en una caja cubica de tal forma que el contorno de la moneda toca las 4 paredes de la caj

a, si la base de la caja tiene un perímetro de 24 cm ¿Cual es el área de la moneda?
Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer: 50.24 cm^2

Step-by-step explanation:

This can be translated to:

An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of ​​the coin?

The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.

The perimeter of the box is 24 cm, and the perimeter of a square is equal to:

P = 4*L

where L is the side lenght of the square.

24 cm = 4*L

L = 24cm/4 = 8cm

Now we know that the diameter of the coin is 8cm

Now, the area of a circle (the coin) is equal to:

A = 3.14*(d/2)^2

where d is the diameter, so we have:

A = 3.14*(4cm)^2 = 50.24 cm^2

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Answer:

yes Amen and we also need Jesus

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The Pacific halibut fishery has been modeled by the differential equation dy dt = ky 1 − y K where y(t) is the biomass (the tota
Dafna1 [17]

Answer:

a. The biomass weighs 2.30 * 10^7 kg after a year

b. It'll take 2.56 years to get to 4*10^7kg

Step-by-step explanation:

a.

k = 0.78,K = 6E7 kg

Given

dy/dt = ky(1- y/K)

Make ky dt the subject of formula

ky dt = dy/(1-y/K) --- make k dt the subject of formula

k dt = dy/(y(1-y/K))

k dt = K dy / y(K-y)

k dt = ((1/y) + (1/(K-y)))dy ---- integrate both sides

kt + c = ln(y/(K-y))

Ce^(kt) = y/(K-y)

Substitute the values of k and K

Ce^(0.78t) = y/(6*10^7 - y) ----- (1)

Given that y(0) = 2 * 10^7kg

(1) becomes

Ce^(0.78*0) = (2 * 10^7)/(6*10^7 - 2*10^7)

Ce° = (2*10^7)/(4*10^7

C = 2/7

Substitute 2/7 for C in (1)

2/7e^0.78t = y/(6*10^7 - y) ---(2)

We're to find the biomass a year later

So, t = 1

2/7e^0.78 = y/(6*10^7 - y)

0.62 = y/(6*10^7 - y)

y = 0.62(6*10^7 - y)

y = 0.62*6*10^7 - 0.62y

y + 0.62y = 0.62*6*10^7

1.62y = 0.62*6*10^7

1.62y = 3.72 * 10^7

y = 2.30 * 10^7kg.

Hence, the biomass weighs 2.30 * 10^7 kg after a year

b.

Here, we're to calculate the time it'll take the biomass to get to 4*10^7 kg

Substitute 4*10^7 for y in (2)

2/7e^0.78t = 4*10^7/(6*10^7 - 4*10^7)

2/7e^0.78t = 4*10^7/2*10^7

2/7e^0.78t = 2

e^0.78t = (2*7)/2

e^0.78t = 2

t = 2 * 1/0.78

t = 2.56 years

Hence, it'll take 2.56 years to get to 4*10^7kg

8 0
3 years ago
Which of the following is not something that you could do with a normal checking account
Svetlanka [38]
Picture?????????????????
6 0
3 years ago
Calculeaza diferenta nr 824532 si 698845 apoi dubleaza rezultatul.
natita [175]

Răspuns:

693860

Explicație pas cu pas:

Diferența dintre: 824532 și 698845

824532 - 698845 = 125687

Dublând rezultatul, r:

2 * 125687 = 251374

Pentru a obține: 3 * 315078 = 945234

Numărul care trebuie adăugat la r, în altul pentru a obține 945234 este:

945234 - 251374 = 693860

Prin urmare, 693860 trebuie adăugat la 251374 pentru a obține (3 * 315078)

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3 years ago
Y=-2x+4
goldenfox [79]
I think it is the first one
5 0
3 years ago
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