Forty-five and twenty-three hundredths.
In general, with decimals, the first place value after the decimal is read as a tenth, the second is read as a hundredth, the third is read as a thousandth, and so on. In front of the decimal, we know that 4 is in the tens place and 5 is in the ones place, so we say forty-five. Past the decimal, 2 is in the tenths place (think about how 2/10 = .2, which is "two-tenths") and 3 is in the hundredths place (think about how 23/100 = .23). You read the number after the decimal like normal ("twenty-three," "two-hundred fifteen," etc), then you add the place ("tenths, hundredths, ten-thousands") at the very end.
Given a quadratic equation
1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.
In our case the coefficient of x is 10, so we write 10 as 2*5
2. then we write +
and -
to the expression:
Answer:
Because 1/2 of 6 =1/3 and 1/2×1/3=1/6
1×5 or 5×1 would be a factual of it
Answer: 31 : 9
Step-by-step explanation:
Assume the following:
Alice's amount = P
Bob's amount = Q
Amount received = n
If Alice receives $n$ dollars from Bob ;then she will have $4$ times as much money as Bob.
P + n = 4(Q - n)
P + n = 4Q - 4n
P = 4Q - 4n - n
P = 4Q - 5n - - - - (1)
If, on the other hand, she gives $n$ dollars to Bob, then she will have $3$ times as much money as Bob
P - n = 3(Q + n)
P - n = 3Q + 3n
P = 3Q + 3n + n
P = 3Q + 4n - - - - - - (2)
Equating both equations - (1) and (2)
4Q - 5n = 3Q + 4n
4Q - 3Q = 4n + 5n
Q = 9n
Express P in terms of n, use either equation (1) or (2)
From equation 2:
P = 3Q + 4n
Substituting Q = 9n
P = 3(9n) + 4n
P = 27n + 4n
P = 31n
Alice's amount = P, Bob's = Q
Ratio = P:Q
31 : 9
