Answer:
y = 7.50 + 1.50x
Step-by-step explanation:
The admission costs $7.50 and after x hours Jon has to pay $1.50*x. Then the cost y in dollars is
y = 7.50 + 1.50x where x is the number of hours.
Hourly rate:
39(1.3r) = 541.80
(hours times hourly rate equals profit)
then solve
1.3r = 13.89
r = 10.69
the hourly rate is $10.69
to answer the bottom question, 390 + 117 = 507, but that’s not close to 541.80 so I have no idea what they’re asking there
Answer:
![\angle C \cong \angle M](https://tex.z-dn.net/?f=%20%5Cangle%20C%20%5Ccong%20%5Cangle%20M%20)
![\angle G \cong \angle P](https://tex.z-dn.net/?f=%20%5Cangle%20G%20%5Ccong%20%5Cangle%20P%20)
![\angle I \cong \angle R](https://tex.z-dn.net/?f=%20%5Cangle%20I%20%5Ccong%20%5Cangle%20R%20)
![\overline{CG} \cong \overline{MP}](https://tex.z-dn.net/?f=%20%5Coverline%7BCG%7D%20%5Ccong%20%5Coverline%7BMP%7D%20)
![\overline{GI} \cong \overline{PR}](https://tex.z-dn.net/?f=%20%5Coverline%7BGI%7D%20%5Ccong%20%5Coverline%7BPR%7D%20)
![\overline{CI} \cong \overline{MR}](https://tex.z-dn.net/?f=%20%5Coverline%7BCI%7D%20%5Ccong%20%5Coverline%7BMR%7D%20)
Step-by-step explanation:
Given the congruence statement ∆CGI
∆MPR, it follows that the corresponding sides of both ∆s are equal, as well as the corresponding vertices or angles. It implies that ∆CGI and ∆MPR are of the same shape and size.
✅Thus, the 6 pairs of the corresponding congruent parts of ∆CGI and ∆MPR are:
![\angle C \cong \angle M](https://tex.z-dn.net/?f=%20%5Cangle%20C%20%5Ccong%20%5Cangle%20M%20)
![\angle G \cong \angle P](https://tex.z-dn.net/?f=%20%5Cangle%20G%20%5Ccong%20%5Cangle%20P%20)
![\angle I \cong \angle R](https://tex.z-dn.net/?f=%20%5Cangle%20I%20%5Ccong%20%5Cangle%20R%20)
![\overline{CG} \cong \overline{MP}](https://tex.z-dn.net/?f=%20%5Coverline%7BCG%7D%20%5Ccong%20%5Coverline%7BMP%7D%20)
![\overline{GI} \cong \overline{PR}](https://tex.z-dn.net/?f=%20%5Coverline%7BGI%7D%20%5Ccong%20%5Coverline%7BPR%7D%20)
![\overline{CI} \cong \overline{MR}](https://tex.z-dn.net/?f=%20%5Coverline%7BCI%7D%20%5Ccong%20%5Coverline%7BMR%7D%20)
<u>Answer:</u>
The value of f(x) =
when x=3 is 19, hence the correct option is ‘d’.
<u>Solution:</u>
A two degree polynomial equation is given in the question.
The equation is:
![F(x)=2 x^{2}+1](https://tex.z-dn.net/?f=F%28x%29%3D2%20x%5E%7B2%7D%2B1)
We need <em>to find the value of f(x) when the value of x is 3.
</em>
To solve a question like this we have to substitute the given value of x in the given equation and then simplify it.
Now let's substitute the value of x in the given equation.
![F(x)=2(3)^{2}+1](https://tex.z-dn.net/?f=F%28x%29%3D2%283%29%5E%7B2%7D%2B1)
First we square the number 3 and then multiply it with 2 and then add 1.
This is done because of the BODMAS rule, in which multiplication is given higher preference as compared to addition.
On solving the equation we get,
F(x)=2×9+1
F(x)=18+1
F(x)=19.
Therefore the value of f(x) when x=3 is 19.
Hence the correct option is ‘d’.
Answer:
See below.
Step-by-step explanation:
1.
5^2 + 12^2 = x^2
25 + 144 = x^2
169 = x^2
x = 13
2.
3^2 + x^2 = [sqrt(10)]^2
9 + x^2 = 10
x^2 = 1
x = 1
3.
1^2 + x^2 = 4^2
1 + x^2 = 16
x^2 = 15
x = sqrt(15)
4.
[sqrt(27)]^2 + x^2 = 6^2
27 + x^2 = 36
x^2 = 9
x = 3
5.
15/5 = c/sqrt(29)
5c = 15 * sqrt(29)
c = 3sqrt(29)
6.
26/13 = x/12
2 = x/12
x = 24